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Chapter 8: Q56P (page 369)

What orbital do the lone-pair electrons occupy in each of the following compounds?

Short Answer

Expert verified

a) Nitrogen is attached with carbon with a single bond hence it is sp3hybridized.

b) Nitrogen is attached with carbon with a double bond hence it is sp2hybridized.

c) Nitrogen is attached with carbon with a triple bond hence it is sphybridized.

Step by step solution

01

How we determine this

a) Nitrogen is attached with carbon with a single bond hence it is sp3hybridized.

b) Nitrogen is attached with carbon with a double bond hence it is sp2hybridized.

c) Nitrogen is attached with carbon with a triple bond hence it is sphybridized.

02

Final answer

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Most popular questions from this chapter

a. How could each of the following compounds be prepared from a hydrocarbon in a single step?

b. What other organic compound would be obtained from each synthesis?

In 1935, J. Bredt, a German chemist, proposed that a bicycloalkene could not have a double bond at a bridgehead carbon unless one of the rings contains at least eight carbons. This is known as Bredt’s rule. Explain why there cannot be a double bond at this position.

a. The following compounds have the same molecular formula as benzene. How many monosubstituted products would each have?

1.HC≡CC≡CCH2CH3 2. CH2≡CHC≡CCH≡CH2

b. How many disubstituted products would each of the preceding compounds have? (Do not include stereoisomers.)

c. How many disubstituted products would each of the compounds have if stereoisomers are included?

a. Draw resonance contributors for the following species, showing all the lone pairs:

1.CH2N2 2. N2O 3. NO2-

b. For each species, indicate the most stable resonance contributor.

What are the products of the following reactions, assuming that one equivalent of each reagent is used in each reaction? Disregard stereoisomers.
See all solutions

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