Question

Draw structures for the following:

a. (2E,4E)-1-chloro-3-methyl-2,4-hexadiene

b. (3Z,5E)-4-methyl-3,5-nonadiene

c. (3Z,5Z)-4,5-dimethyl-3,5-nonadiene

d. (3E,5E)-2,5-dibromo-3,5-octadiene

Short answer

Here we have to draw the structures of following compounds:

Step-by-step solution

How to do naming of these compounds:

This naming is done according to IUPAC nomenclature:

1. Select longest parent chain.

2. Functional group has to be given lowest number.

3. If two Functional groups are present then give number according to priority order.

Steps to draw E and Z isomers

1. Assign the priority order to the groups on the basis of atomic number. Higher the atomic number get highest priority.

2. If higher priority groups are on same side then it will be Z isomer.

3. If higher priority groups are on different side then it will be E isomer.

How to give priority 

1. Assign the priority order to the groups on the basis of atomic number. Higher the atomic number get highest priority.

2. Double bond is considered as carbon is attached to 2 carbons.

3. Triple bond is considered as carbon is attached to 3 carbons.