Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Show the intermediate that would result if the growing chain added to the other end of the styrene double bond. Explain why the final polymer has phenyl groups substituted on alternate carbon atoms rather than randomly distributed.

Short Answer

Expert verified

Show the intermediate that would result if the growing chain added to the other end of the styrene double bond. Explain why the final polymer has phenyl groups substituted on alternate carbon atoms rather than randomly distributed.

Step by step solution

01

Step-1. Chain-growth polymerisation:

Chain-growth polymerisation is the formation of polymers from unsaturated monomers. There occurs no rapid loss of monomers at the beginning and an active site can be observed at the end of the polymer chain. It requires initiators to break the double bond in monomer molecule.

02

Step-2. Reason for why final polymer has phenyl substituents on alternate carbons:

Orientation of addition always generates the more stable intermediate, that is, the energy difference between a primary radical and a benzylic radical is huge, the primary radical is not resonance stabilised and thus the orientation will not be observed in which chain growth occurs through primary radical. Thus, the phenyl substituents must necessarily be on alternating carbons as orientation of attack will always be the same and not random.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Polychloroprene, commonly known as neoprene, is widely used in wetsuits and in rubber parts that must withstand exposure to gasoline or other solvents.

(a) Is neoprene an addition polymer or a condensation polymer?

(b) What monomer is used to make this synthetic rubber?

Compare the molecular structures of cotton and polypropylene, the two major components of thermal underwear. One of these gets wet easily and holds the water in contact with the skin. The other one does not get wet, but wicks the water away from the skin and feels relatively dry to the touch. Explain the difference in how these two fabrics respond to moisture.

Glyptalยฎresin makes a strong, solid polymer matrix for electronic parts. Glyptal is made from terephthalic acid and glycerol. Draw the structure of Glyptal and explain its remarkable strength and rigidity.

Chain branching occurs in cationic polymerization much as it does in free-radical polymerization. Propose a mechanism to show how branching occurs in the cationic polymerization of styrene. Suggest why isobutylene might be a better monomer for cationic polymerization than styrene.

Plywood and particle board are often glued with cheap, waterproof urea-formaldehyde resins. Two to three moles of formaldehyde are mixed with one mole of urea and a little ammonia as a basic catalyst. The reaction is allowed to proceed until the mixture becomes syrupy, and then it is applied to the wood surface. The wood surfaces are held together under heat and pressure, while polymerization continues and cross-linking takes place. Propose a mechanism for the base-catalyzed condensation of urea with formaldehyde to give a linear polymer, and then show how further condensation leads to cross-linking. (Hint: The carbonyl group lends acidity to the N - Hprotons of urea. A first condensation with formaldehyde leads to an imine, which is weakly electrophilic and reacts with another deprotonated urea.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free