Question

Draw the structure that corresponds with each name.

(a)$\text{3-ethyloctane}$

(b)$\text{4-isopropyldecane}$

(c)$\sec \text{-butylcycloheptane}$

(d)$\text{2,3-dimethyl-4-propylnonane}$

(e)$\text{2,2,4,4-tetramethylhexane}$

(f)$trans\text{-1,3-diethylcyclopentane}$

(g)$cis\text{-1-ethyl-4-methylcyclohexane}$

(h)$\text{isobutylcyclopentane}$

(i)$tert\text{-butylcyclohexane}$

(j)$\text{pentylcyclohexane}$

(k)$\text{cyclobutylcyclohexane}$

(l)$cis\text{-1-bromo-3-chlorocyclohexane}$

Short answer

a)

b)

c)

d)

e)

f)

g)

h)

i)

j)

k)

l)

Step-by-step solution

Drawing cis and transisomers for cycloalkanes

In the case of cycloalkanes, if the two substituents point toward the same faces, they are known as cis isomers. Again, if the two substituents point toward the opposite faces, they are known as the trans isomer. These two geometric isomers cannot interconvert without breaking and forming the bonds again.

Structure corresponding to the given name

Each structure is drawn from its given name.

a)

b)

c)

d)

e)

f)

g)

h)

I)

j)

k)

l)