Question

Give the molecular formula of each compound shown in Problem 1-37.

Short answer

1. The molecular formula for the given compound is ${\text{C}}_6{\text{H}}_{\text{6}}\text{O}$.
2. The molecular formula for the given compound is ${\text{C}}_{\text{4}}{\text{H}}_{\text{5}}\text{N}$.
3. The molecular formula for the given compound is ${\text{C}}_{\text{4}}{\text{H}}_{\text{8}}{\text{O}}_{\text{2}}$.
4. The molecular formula for the given compound is ${\text{C}}_{\text{6}}{\text{H}}_{\text{8}}{\text{O}}_{\text{2}}$.
5. The molecular formula for the given compound is${\text{C}}_{\text{7}}{\text{H}}_{\text{10}}$ .
6. The molecular formula for the given compound is${\text{C}}_{\text{4}}{\text{H}}_{\text{4}}\text{O}$ .
7. The molecular formula for the given compound is ${\text{CH}}_{\text{3}}{\text{O}}_{\text{2}}\text{N}$.
8. The molecular formula for the given compound is ${\text{C}}_{\text{6}}{\text{H}}_{\text{10}}\text{O}$.

Step-by-step solution

Molecular formula

A molecular formula is a kind of a representation of a molecule which comprises of the usage of chemical symbols. It indicates the types of atoms followed by subscripts that shows the number of atoms of each type in the molecule.

Drawing the open structures of all compounds

Draw the all the atoms represented in the bond line notation and satisfy their valency by adding the hydrogens as shown for all the compounds below.

a.

This is an open structure of the given compound and its common name is phenol.

b.

This is an open structure of the given compound and its common name is pyrrole.

c.

This is an open structure of the given compound and its common name is 1,4-dioxane.

d.

This is an open structure of the given compound and its common name is 1,4-dioxane.

e.

This is an open structure of the given compound:

f.

This is an open structure of the given compound:

g.

This is an open structure of the given compound:

h.

This is an open structure of the given compound:

Molecular formula for each compound

Write the symbol of atom along with the total number of times it is present in the compound in its subscript as shown below for each compound.

a. In the given compound, there are 6 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom. So, the molecular formula for the compound becomes ${\text{C}}_6{\text{H}}_{\text{6}}\text{O}$.

b. In the given compound, there are 4 carbon atoms, 5 hydrogen atoms, and 1 nitrogen atom. So, the molecular formula for the compound becomes ${\text{C}}_{\text{4}}{\text{H}}_{\text{5}}\text{N}$.

c. In the given compound, there are 4 carbon atoms, 8 hydrogen atoms, and 2 oxygen atoms. So, the molecular formula for the compound becomes ${\text{C}}_{\text{4}}{\text{H}}_{\text{8}}{\text{O}}_{\text{2}}$.

d. In the given compound, there are 6 carbon atoms, 8 hydrogen atoms, and 2 oxygen atoms. So, the molecular formula for the compound becomes ${\text{C}}_{\text{6}}{\text{H}}_{\text{8}}{\text{O}}_{\text{2}}$.

e. In the given compound, there are 7 carbon atoms and 10 hydrogen atoms. So, the molecular formula for the compound becomes ${\text{C}}_{\text{7}}{\text{H}}_{\text{10}}$.

f. In the given compound, there are 4 carbon atoms, 4 hydrogen atoms, and 1 oxygen atom. So, the molecular formula for the compound becomes ${\text{C}}_{\text{4}}{\text{H}}_4{\text{O}}_{}$.

g. In the given compound, there are 1 carbon atom, 3 hydrogen atoms, 2 oxygen atom, and 1 nitrogen atom. So, the molecular formula for the compound becomes ${\text{CH}}_{\text{3}}{\text{O}}_2{\text{N}}_{}$.

h. In the given compound, there are 6 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom. So, the molecular formula for the compound becomes ${\text{C}}_{\text{6}}{\text{H}}_{\text{10}}{\text{O}}_{}$.