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Under normal circumstances, tertiary alcohols are not oxidized. However, when the tertiary alcohol is allylic, it can undergo a migration of the double bond (called an allylic shift) and subsequent oxidation of the alcohol. A particularly effective reagent for this reaction is Bobbitt’s reagent, similar to TEMPO used in many oxidations. (M. Shibuya et al., J. Org. Chem., 2008, 73, 4750.)

Show the expected product when each of these 3° allylic alcohols is oxidized by Bobbitt’s reagent.

(a)

(b)

(c)

(d)

Short Answer

Expert verified

The organic reagent that bears nitrogen and ketone groups and exists in salt form is Bobbitt’s reagent.

This compound is invented by James M. Bobbitt. This reagent is used for the preparation of alkaloids namely salsoline, carnegine, salsolidine, and lophocerine.

Step by step solution

01

About Bobbitt’s reagent

The organic reagent that bears nitrogen and ketone groups and exists in salt form is Bobbitt’s reagent.

This compound is invented by James M. Bobbitt. This reagent is used for the preparation of alkaloids namely salsoline, carnegine, salsolidine, and lophocerine.

02

Reaction of the first compound with Bobbitt’s reagent

A carbonyl group will be generated in the ring, and the double bond shift takes place. The OH group will be removed and the reaction is shown below.

03

Reaction of the second compound with Bobbitt’s reagent

A carbonyl group will be generated and the double bond shift takes place. The OH group will be removed and the reaction is shown below.

04

Reaction of the third compound with Bobbitt’s reagent

There will be the generation of a carbonyl group and the double bond shift takes place. The OH group will be removed. The reaction is shown below.

05

Reaction of the fourth compound with Bobbitt’s reagent

A carbonyl group will be generated and a double bond shift takes place. The OH group will be removed and the reaction is shown below.

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Most popular questions from this chapter

(a) The reaction of butan-2-ol with concentrated aqueous HBr goes with partial racemization, giving more inversion than retention of configuration. Propose a mechanism that accounts for racemization with excess inversion.

(b)Under the same conditions, an optically active sample of trans-2-bromocyclopentanol reacts with concentrated aqueous HBr to give an optically inactive product, (racemic) trans-1,2-dibromocyclopentane. Propose a mechanism to show how this reaction goes with apparently complete retention of configuration, yet with racemization. (Hint: Draw out the mechanism of the reaction of cyclopentene with in water to give the starting material, trans-2- bromocyclopentanol. Consider how parts of this mechanism might be involved in the reaction with HBr.)

Write balanced equations for the three preceding reactions.

Predict the products of the reactions of the following compounds with:

(1) chromic acid or excess sodium hypochlorite with acetic acid.

(2)PCC or NaOCl (1 equivalent) with TEMPO.

(a)cyclohexanol (b)1-methylcyclohexanol

(c)cyclopentylmethanol (d)cyclohexanone

(e)cyclohexane (f)1-phenylpropan-1-ol

(g)hexan-1-ol (h)acetaldehyde, CH3CHO

Show how you would synthesize the following compounds. As starting materials, you may use any alcohols containing four or fewer carbon atoms, cyclohexanol, and any necessary solvents and inorganic reagents.

Compound A is an optically active alcohol. Treatment with chromic acid converts A into a ketone, B. In a separate reaction, A is treated with PBr3, converting A into compound C. Compound C is purified, and then it is allowed to react with magnesium in ether to give a Grignard reagent, D. Compound B is added to the resulting solution of the Grignard reagent. After hydrolysis of the initial product (E), this solution is found to contain 3,4 dimethylhexan-3-ol. Propose structures for compounds A, B, C, D, and E.

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