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Give the structures of the products you would expect when each alcohol reacts with

(1) HCl, ZnCl2; (2) HBr; (3) PBr3; (4) P/I2; and (5) SOCl2.

(a) butan-1-ol (b) 2-methylbutan-2-ol

(c) 2,2-dimethylbutan-1-ol (d) cis-3-methylcyclopentanol

Short Answer

Expert verified

(a)

(b)

(c)

(d)

Step by step solution

01

Step 1: butan-1-ol reaction with given reactant to form the products

  1. Butan-1-ol is primary alcohol; it reacts with Lucas reagent (HCl/ZnCl2) very slowly Because the activated primary alcohol cannot form a carbocation. It remains in solution until the chloride ion attacks it, forming the product 1-chloro butane.
  2. Butan-1-ol is the primary alcohol that reacts with HBr by the SN2 mechanism to form product 1-bromo butane.

  3. Butan-1-ol is the primary alcohol reacting it with Phosphorus tribromide is often the best reagent for converting it into primary alkyl bromide, thus forming product 1-Bromo butane.

  4. Butan-1-ol is the primary alcohol reacting it with phosphorus/iodine combination (P/l2) is often the best reagent for converting it into primary alkyl iodide, thus forming product 1-iodobutane.

  5. Butan-1-ol is the primary alcohol reacting it with thionyl chloride (SOCl2) convert it into alkyl chloride, naming 1-chlorobutane.


Products formed when reacting with butan-1-ol

02

 2-methyl butane-2-ol reaction with given reactant to form the products

  1. 2-methyl butane-2-olis secondary alcohol; it reacts with Lucas reagent (HCl/ZnCl2) for about 1 to 5 minutes because their secondary carbocations are more stable than primary ones forming the product 2-chloro-2 methyl butane.
  2. 2-methyl butane-2-olis secondary alcohol that reacts with HBr by the SN1 mechanism to form product 2-bromo-2 methyl butane.

  3. 2-methyl butane-2-olis secondary alcohol; it reacts with Phosphorus tribromide and converts into secondary alkyl bromide, thus forming product 2-bromo-2 methyl butane.

  4. 2-methyl butane-2-olis secondary alcohol reacting it with phosphorus/iodine combination (P/l2) is often the best reagent for converting it into secondary alkyl iodide, thus forming product 2-iodo-2 methyl butane.

  5. 2-methyl butane-2-olis secondary alcohol reacting it with thionyl chloride (SOCl2 ) convert it into alkyl chloride, naming 2-chloro-2 methyl butane.

Products formed when reacting with 2-methyl butane-2-ol

03

2,2-dimethylbutan-1-ol reaction with given reactant to form the products

  1. 2,2-dimethylbutan-1-olis primary alcohol; it reacts with Lucas reagent (HCL/ZnCl2 ) very slowly Because the activated primary alcohol cannot form a carbocation. It remains in solution until the chloride ion attacks it, forming the product 3-chloro-3methyl pentane.
  2. 2,2-dimethylbutan-1-olis the primary alcohol that reacts with HBr by the SN2 mechanism to form a product mixture of products 1-bromo 2,2- dimethyl butane, and 3-bromo-3-methyl pentane

  3. 2,2-dimethylbutan-1-ol is the primary alcohol reacting it with Phosphorus tribromide is often the best reagent for converting it into primary alkyl bromide, thus forming product1-bromo 2,2- dimethyl butane.

  4. 2,2-dimethylbutan-1-ol is the primary alcohol reacting it with phosphorus/iodine combination (P/l2 )is often the best reagent for converting it into primary alkyl iodide, thus forming product 1-iodo-2,2-dimethyl butane.

  5. 2,2-dimethylbutan-1-ol is the primary alcohol reacting it with thionyl chloride (SOCl2 ) convert it into alkyl chloride, naming 1-chlo-2,2-dimethyl butane.

Products formed when reacting with 2,2-dimethylbutan-1-ol

04

cis-3-methylcyclopentanol reaction with given reactant to form the products

  1. cis-3-methylcyclopentanolis secondary alcohol; it reacts with Lucas reagent (HCl/ZnCl2 ) for about 1 to 5 minutes because their secondary carbocations (chloride ion attack from either side ) are more stable than primary ones forming the mixture of products (1S,3R)-1-chloro-3-methyl cyclopentaneand(2S,5S)-2-chloro-5-methyl cyclopentane-1-ylium.
  2. cis-3-methylcyclopentanolis secondary alcohol that reacts with HBr by the SN1 mechanism to form a mixture of products (1S,3R)-1-bromo-3-methyl cyclopentaneand(2S,5S)-2-bromo-5-methyl cyclopentane-1-ylium.

  3. cis-3-methylcyclopentanolis secondary alcohol; it reacts withPhosphorus tribromide and converts into secondary alkyl bromide, thus forming product(1R,3R)-1-bromo-3-methyl cyclopentane.

  4. cis-3-methylcyclopentanolis secondary alcohol reacting it with phosphorus/iodine combination (P/l2 ) is often the best reagent for converting it into secondary alkyl iodide, thus forming product (1R,3R)-1-iodo-3-methyl cyclopentane.

  5. cis-3-methylcyclopentanolis secondary alcohol reacting with thionyl chloride (SOCl2 ) convert it into alkyl chloride, naming (1S,3R)-1-chloro-3-methyl cyclopentane.



    Products formed when reacting with cis-3-methylcyclopentanol

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Most popular questions from this chapter

Propose a mechanism for each reaction.

(a)

(b)

Compound A is an optically active alcohol. Treatment with chromic acid converts A into a ketone, B. In a separate reaction, A is treated with PBr3, converting A into compound C. Compound C is purified, and then it is allowed to react with magnesium in ether to give a Grignard reagent, D. Compound B is added to the resulting solution of the Grignard reagent. After hydrolysis of the initial product (E), this solution is found to contain 3,4 dimethylhexan-3-ol. Propose structures for compounds A, B, C, D, and E.

Unknown Q is determined to have a molecular formula of C6H12O. Q is not optically active, and passing it through a chiral column does not separate it into enantiomers. Q does not react with Br2, nor with cold, dilute KMnO4 , nor does it take up H2under catalytic hydrogenation. Heating of Q with H2SO4 gives product R, of formula C6H10, which can be separated into enantiomers. Ozonolysis of a single enantiomer of R produces S, an acyclic, optically active ketoaldehyde of formula C6H10O2. Propose structures for compounds Q, R, and S, and show how your structures would react appropriately to give these results.

The compound shown below has three different types of OH groups, all with different acidities. Show the structure produced after this compound is treated with different amounts of NaH followed by a methylating reagent. Add a brief explanation.

(a)1 equivalent of NaH, followed by 1 equivalent of CH3l and heat

(b)2 equivalents of NaH, followed by 2 equivalents of CH3l and heat

(c) 3 equivalents of NaH, followed by 3 equivalents of CH3l and heat

Chromic acid oxidation of alcohol (Section 11-2A) occurs in two steps: formation of the chromate ester, followed by an elimination of chromium. Which step do you expect to be rate-limiting? Careful kinetic studies have shown that Compound A undergoes chromic acid oxidation over 10 times as fast as Compound B. Explain this large difference in rates.

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