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Five proton NMR spectra are given here, together with molecular formulas. In each case, propose a structure that is consistent with the spectrum.

Short Answer

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  1. The formula has one element of unsaturation. The singlet at chemical shift 12.1 indicates a carboxylic acid. The multiplet and the doublet indicates an isopropyl group. The proposed structure from the spectrum data will be,
  2. The formula has five elements of unsaturation. The pattern between chemical shift 7.2 and 7.4 indicates monosubstituted benzene. The peak at chemical shift 9.85 is an aldehyde trying to be a triplet because it is weakly coupled to an adjacent methylene group. The two triplets at chemical shift 2.7-3.0 are adjacent methylene groups. The proposed structure will be,
  3. The formula has two elements of unsaturation. A singlet at chemical shift 2.3 is probably a methyl next to carbonyl. The quartet and a triplet are certain to be ethyl with the methylene at chemical shift 2.7 and this also appears next to carbonyl. The proposed structure will be,
  4. The formula has one element of unsaturation. Signals from chemical shift 5 to 6 indicates a vinyl pattern. The complex quartet for at chemical shift value 4.3 is a bonded to an alcohol next to methyl group. The hydroxyl appears as a singlet at chemical shift 2.5 and the methyl next to methine carbon is a doublet at chemical shift 1.3. We have following proposed structure,
  5. The formula is saturated. The oxygen must be an alcohol or an ether and the broad peak at chemical shift 1.2 is probably a hydroxyl group. The expansion of multiplet at chemical shift 1.7 shows seven peaks, a septet which indicates an isopropyl group. Six of the nine protons in the pattern at chemical shift 0.9 must be doublet from two methyls from the isopropyl. The quartet at chemical shift 1.5 must be part of an ethyl pattern from which the methyl triplet must be the other of the pattern at chemical shift 0.9. This leaves only a singlet at chemical shift 1.1 which must be methyl with no neighbouring hydrogens. We have the following fragments,

    These fragments can be assembled in a way, that the proposed structure will be,

Step by step solution

01

Step-1. Explanation of part (a):

NMR spectroscopy plays a major role in the determination of the structures and dynamics of proteins and other biological macromolecules. Chemical shifts are the most readily and accurately measurable NMR parameters.

In part (a), The formula has one element of unsaturation. The singlet at chemical shift 12.1 indicates a carboxylic acid. The multiplet and the doublet indicates an isopropyl group. The proposed structure from the spectrum data will be,

Proposed structure from spectrum (a)

02

Step-2. Explanation of part (b):

NMR spectroscopy plays a major role in the determination of the structures and dynamics of proteins and other biological macromolecules. Chemical shifts are the most readily and accurately measurable NMR parameters.

In part (b), the formula has five elements of unsaturation. The pattern between chemical shift 7.2 and 7.4 indicates monosubstituted benzene. The peak at chemical shift 9.85 is an aldehyde trying to be a triplet because it is weakly coupled to an adjacent methylene group. The two triplets at chemical shift 2.7-3.0 are adjacent methylene groups. The proposed structure will be,

Proposed structure from spectrum (b)

03

Step-3. Explanation of part (c):

NMR spectroscopy plays a major role in the determination of the structures and dynamics of proteins and other biological macromolecules. Chemical shifts are the most readily and accurately measurable NMR parameters.

In part (c), the formula has two elements of unsaturation. A singlet at chemical shift 2.3 is probably a methyl next to carbonyl. The quartet and a triplet are certain to be ethyl with the methylene at chemical shift 2.7 and this also appears next to carbonyl. The proposed structure will be,

Proposed structure from spectrum (c)

04

Step-4. Explanation of part (d):

NMR spectroscopy plays a major role in the determination of the structures and dynamics of proteins and other biological macromolecules. Chemical shifts are the most readily and accurately measurable NMR parameters.

In part (d), the formula has one element of unsaturation. Signals from chemical shift 5 to 6 indicates a vinyl pattern. The complex quartet for at chemical shift value 4.3 is a bonded to an alcohol next to methyl group. The hydroxyl appears as a singlet at chemical shift 2.5 and the methyl next to methine carbon is a doublet at chemical shift 1.3. We have following proposed structure,

Proposed structure from spectrum (d)

05

Step-5. Explanation of part (e):

NMR spectroscopy plays a major role in the determination of the structures and dynamics of proteins and other biological macromolecules. Chemical shifts are the most readily and accurately measurable NMR parameters.

In part (e), the formula is saturated. The oxygen must be an alcohol or an ether and the broad peak at chemical shift 1.2 is probably a hydroxyl group. The expansion of multiplet at chemical shift 1.7 shows seven peaks, a septet which indicates an isopropyl group. Six of the nine protons in the pattern at chemical shift 0.9 must be doublet from two methyls from the isopropyl. The quartet at chemical shift 1.5 must be part of an ethyl pattern from which the methyl triplet must be the other of the pattern at chemical shift 0.9. This leaves only a singlet at chemical shift 1.1 which must be methyl with no neighbouring hydrogens. We have the following fragments,

These fragments can be assembled in a way, that the proposed structure will be,

Proposed structure from spectrum (e)

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Most popular questions from this chapter

Phenyl Grignard reagent adds to 2-methylpropanal to give the secondary alcohol shown. The proton NMR of 2-methylpropanal shows the two methyl groups as equivalent (one doublet at1.1), yet the product alcohol, a racemic mixture, shows two differentdoublets, one at0.75 and one around1.0.

  1. Draw a Newmann projection of the product along the C1-C2 axis.
  2. Explain why the two methyl groups have different NMR chemical shifts. What is the term applied to protons such as these?

An inexperienced graduate student was making some 4-hydroxybutanoic acid. He obtained an excellent yield of a different compound, whose 13CNMR spectrum is shown here.

  1. Propose a structure for this product.
  2. Assign the peaks in the 13CNMR spectrum to the carbon atoms in the structure.

For each compound shown below,

  1. Sketch theC13NMR spectrum (totally decoupled, with a singlet for each type of carbon), showing approximate chemical shifts.
  2. Show the multiplicity expected for each signal in the off-resonance-decoupled spectrum.
  3. Sketch the spectra expected using the DEPT-90 and DEPT-135 techniques.

A new chemist moved into an industrial lab where work was being done on oxygenated gasoline additives. Among the additives that had been tested, she found an old bottle containing a clear, pleasant-smelling liquid that was missing its label. She took the quick NMR spectrum shown and was able to determine the identity of the compound without any additional information. Propose a structure and assign the peaks. (Hint: This is a very pure sample.)

Different types of protons and carbons in alkanes tend to absorb at similar chemical shifts, making structure determination difficult. Explain how the among the following four isomer 13C NMR spectrum, including the DEPT technique, would allow you to distinguish.

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