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Question: Four infrared spectra are shown, corresponding to four of the following compounds. For each spectrum, determine the structure and explain how the peaks in the spectrum correspond to the structure you have chosen

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01

IR-spectroscopy

Each organic functional group has a characteristic IR- absorption frequency. Based on that, the structure of the compound can be deduced.

02

Subpart (a)

The given spectrum indicates a broad peak at3400cm-1,-2500cm-1 and confirms the presence of –OH group with C-H stretching.

A peak at1710cm-1 represents the C=O stretch in carboxylic acid.

A peak at 1660cm-1represents C=C stretching.

From this data, it is clear that the given compound has the below shown structural formula:

Structure (a)

03

Subpart (b)

The given spectrum indicates the characteristic peak . This represents the C-H stretch.

A characteristic peak at1710cm-1 represents the C=O stretch.

Hence, the structure of the compound is as shown below:

Structure (b)

04

 Step 3: Subpart (b)

The given spectrum indicates the characteristic peak 3000cm-1-2840cm-1. This represents the C-H stretch.

A characteristic peak at1710cm-1 represents the C=O stretch.

Hence, the structure of the compound is as shown below:

Structure (b)

05

Subpart (c)

The peak at2900cm-1 represents the presence of C-H stretch.

The peak at 2260cm-1represents stretch.

The peak The peaks between 1600cm-1-1400cm-1represents the C=C stretch in benzene.

Hence, the structure of the compound that represents the given IR spectrum is shown below:

Structure (c)

06

Subpart (d)

A characteristic broad IR peak 3500cm-1-3300cm-1is observed .It represents the presence of O-H group.

A peak between 3000cm-1-2800cm-1represents the C-H stretch.

The peaks between1600cm-1-1400cm-1 represents the C=C stretch in benzene.

Hence, the structure of the compounds for the given IR spectrum is as shown below:

Structure (d)

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Most popular questions from this chapter

Convert the following infrared wavenumbers into wavelengths.

(a) 1600cm-1, typical for an aromatic

(b) 3000cm-1, typical for a saturated bond

(c) 1715cm-1, typical for a ketone carbonyl

(d) 1750cm-1, typical for an ester carbonyl

(e) 2220cm-1, typical for a nitrile

(f) 3300cm-1, typical for an alcohol

Question: Show the fragmentation that accounts for the cation at m/z 57 in the mass spectrum of 2-methylpentane. Explain why this ion is less abundant than those at m/z 71 and 43.

A laboratory student added 1-bromobutane to a flask containing dry ether and magnesium turnings. An exothermic reaction resulted, and the ether boiled vigorously for several minutes. Then she added acetone to the reaction mixture and the ether boiled even more vigorously. She added dilute acid to the mixture and separated the layers. She evaporated the ether layer, and distilled a liquid that boiled at 143C. role="math" localid="1649504068494" GC-MSanalysis of the distillate showed one major product with a few minor impurities. The mass spectrum of the major product is shown here.

(a) Draw out the reactions that took place and show the product that was formed.

(b) Explain why the molecular ion is not visible in the mass spectrum, and show what ions are likely to be responsible for the strong peaks at m/z, 59 and 101.

Predict the masses and the structures of the most abundant fragments observed in the mass spectra of the following compounds

a. 2-methylpentane

b. 3-methylhex-2-ene

c. 4-methylpentane-2-ol

d. 2-methyl-1-phenylpropane

e. Cyclohexylisopropy; ether [cyclohexyl--O-CH(CH3)2 ]

f. CH3CH2CH2NHC(CH3)2

g.

h.3-bromo-2-methylpentane

Chapter-9 covered a synthesis of alkynes by a double dehydrohalogenation of dihalides. A student tried to convert trans-2,5-dimethylhex-3-yne by adding bromine across the double bond and then doing a double elimination. The infrared and mass spectra of the major product are shown here.

  1. Do the spectra confirm the right product? If not, what is it?
  2. Explain the important peaks in the IR spectrum.

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