Question

Predict the products from this sequence of reactions

Short answer

It is the reaction of the enolate ion with another carbonyl group that leads to the form $\mathrm{\alpha },\mathrm{\beta }$ unsaturated aldehyde or ketone.

Step-by-step solution

Step-by-Step Solution Step1: Aldol self-condensation

It is the reaction of the enolate ion with another carbonyl group that leads to the form $\mathrm{\alpha },\mathrm{\beta }$ unsaturated aldehyde or ketone.

Formation of the product

As the hydrogen is protonated from the reacting species formation of enolate ion occurs which combines with another group of carbonyl followed by the removal of ${\mathrm{OH}}^{-}$ formation of$\mathrm{\alpha },\mathrm{\beta }$ unsaturated aldehyde occur.

Formation of the product followed by alkylation

Ethoxide is used as the base to form an enolate ion which forms$\mathrm{\beta }$ keto ester on further reaction with the alkyl halide the alkylation occurs means the by removal of halide ion the alkyl group attached at the alpha position to the carbonyl

Mechanism

1. Acidic hydrogen protonated
2. Formation of enolate ion
3. Aldol condensation
4. Alkylation

Aldol self-Condensation