Question

Show how you would accomplish the following conversions in good yields. You may use any necessary reagents.

Short answer

Reagent used is${\mathrm{I}}_2\mathrm{Excess}$

Step-by-step solution

Step-by-Step Solution

Step1: Reagent

A reagent is a substance that is added in the reaction to form the product from the reaction means they are used to complete the chemical reactions.

Haloform reaction

The reaction occurs with the ketone in which halogenation occurs at the alpha carbon or the methyl carbon of ketone and halogenation is occur three times from trihalomethane ketone which is a best leaving group then by proton transfer formation of acid occurs.

Reagent used in the reaction

As per the reaction, a haloform reaction occurs in which iodine is used as a reagent which is an oxidizing agent it replaces the alpha halogen to form trihalomethane ketone by doing halogenation three times which is the best leaving group.

Product formation in the presence of a reagent

As per the reaction, a carboxylate ion is formed which means after the formation of trihalomethane ketone by iodine which act as the best leaving group followed by the removal of leaving group carbon gain negative charge and carboxylate ion formed if hydrolysis occur then carboxylic acid formed.

Product Formation