Question

Show how you would synthesize each compound, starting with an ester containing no more than eight carbon atoms. Any other necessary reagents may be used.

e. PhCH₂OH

Short answer

Answer

The synthesis of the given compound is given below.

Step-by-step solution

Use of reagent LiAlH4

LiAlH₄is a strong reducing agent for polar double bonds, as it is easily thought of as a source of . It reduces aldehydes, ketones, esters, carboxylic acid chloride, and carboxylic acids to alcohol PhCH₂OH OH^-.

Formation of PhCH2OH

Ester in the presence of reducing agent forms primary alcohol. In this reaction, ester in the presence of reducing agent LiAlH₄ results in the formation of primary alcohol,PhCH₂OH.

Subpart e