Question

Draw the following sugar derivatives.

1. ethyl-$\mathbf{\beta }$-D-glucopyranoside
2. 2,3,4,6-tetra-O-ethyl-D-mannopyranose
3. 1,3,6-tri-O-ethyl-D-fructofuranose
4. Ethyl-2,3,4,6-tetra-O-methyl-$\mathbf{\beta }$-D-galactopyranoside

Short answer

Answer :

Step-by-step solution

Diagrams of the given sugar derivates:

Pyranose is a cyclic hemiacetal form of a monosaccharide having a six-membered ring whereas pyranoside is glycoside form of pyranose. Furanose can be either hemiacetal or hemiketal and possess five-membered ring structure which consist of carbon and oxygen atoms.

2,3,4,6-tetra-O-ethyl-D-mannopyranose

1,3,6-tri-O-ethyl-D-fructofuranose

ethyl-2,3,4,6-tetra-O-methyl--D-galactopyranoside

ethyl--D-glucopyranoside

Naming of the sugar derivates

The carbohydrate part of the molecule is known as glycone and the -O- bridge is glycosidic oxygen. The linkage present is named in the middle of the pyranoside or furanose or pyranose sugar. Saccharide name ends with ‘ide’ or ‘ose’.