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Except for the Tollens test, basic aqueous conditions are generally avoided with sugars because they lead to fast isomerizations.

  1. Under basic conditions, the proton alpha to the aldehyde (or ketone) carbonyl group is reversibly removed, and the resulting enolate ion is no longer asymmetric. Reprotonation can occur on either face of the enolate, giving either the original structure or its epimer. Because a mixture of epimer results, this process is called epimerization. Propose a mechanism for the base-catalyzed equilibration of glucose to a mixture of glucose and its C2 epimer, mannose.
  2. Propose a mechanism for the isomerization of a ketose to an aldose, via the enediol intermediate, shown immediately above. Note that the enediol has twoprotons and removing one or the other gives two different enolate ions.

Short Answer

Expert verified

In base catalyzed reaction, as D-glucose has epimeric carbon and it is chiral, thus, in presence of base, firstly, base abstracts proton from epimeric carbon which leads to the formation of carbanion. Enolate is formed which is planar from either side, that is, one side will lead to the formation of glucose and other side will lead to the formation of mannose. Then, after hydrolysis, we get our required products. D-glucose and D-mannose are C2 epimers.

D-glucose D-mannose

Base-catalyzed mechanism of conversion of D-glucose to its C2 epimer D-mannose

Step by step solution

01

Step-1. Explanation of part (a):

In base catalyzed reaction, as D-glucose has epimeric carbon and it is chiral, thus, in presence of base, firstly, base abstracts proton from epimeric carbon which leads to the formation of carbanion. Enolate is formed which is planar from either side, that is, one side will lead to the formation of glucose and other side will lead to the formation of mannose. Then, after hydrolysis, we get our required products. D-glucose and D-mannose are C2 epimers.

D-glucose D-mannose

Base-catalyzed mechanism of conversion of D-glucose to its C2 epimer D-mannose

02

Step-2. Explanation of part (b):

Ketose to aldose conversion occurs via enolate and ene-diol formation. Base abstracts acidic proton in first step from alpha carbon of ketose which leads to the formation of carbanion which is resonance stabilised. Then, formation of ene-diol intermediate occurs from which base again abstracts proton and forms enolate which after hydrolysis leads to generation of an aldose. All of these steps are reversible.

Mechanism of conversion of ketose to an aldose

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Most popular questions from this chapter

Draw the Haworth projection for the cyclic structure of D-mannose by laying down the Fischer projection.

The Wohl degradation, an alternative to the Ruff degradation, is nearly the reverse of the Kiliani-Fischer synthesis. The aldose carbonyl group is converted to the oxime, which is dehydrated by acetic anhydride to the nitrile (a cyanohydrin). Cyanohydrin formation is reversible, and a basic hydrolysis allows the cyanohydrin to lose HCN. Using the following sequence of reagents, give equations for the individual reaction in the Wohl degradation of D-arabinose to D-erythrose. Mechanisms are not required.

(1) hydroxylamine hydrochloride

(2) acetic anhydride

(3) OH-,H2O

Aldohexoses A and B both undergo Ruff degradation to give aldopentose C. On treatment with warm nitric acid, aldopentose C gives an optically active aldaric acid. B also reacts with warm nitric acid to give an optically active aldaric acid, but A reacts to give an optically inactive aldaric acid. Aldopentose C is degraded to aldotetrose D, which gives optically active tartaric acid when it is treated with nitric acid. Aldotetrose D is degraded to (+)-glyceraldehyde. Deduce the structures of sugars A,B,C and D, and use Figure 23-3 to determine the correct names of these sugars.

Emil Fischer synthesized L-gulose, an unusual aldohexose that reduces to give D-glucitol. Suggest a structure for this L sugar, and show how L-gulose gives the same alditol as D-glucose. (Hint: D-Glucitol has -CH2OHgroups at both ends. Either of these primary alcohol groups might have come from reduction of an aldehyde.)

Like glucose, galactose mutarotates when it dissolves in water. The specific rotation of ฮฑ-D-galactopyranoseis +150.70 , and that of the ฮฒ anomer is +52.80 . When either of the pure anomers dissolves in water, the specific rotation gradually changes to +80.20. Determine the percentages of the two anomers present at equilibrium.

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