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Draw the following monosaccharides, using chair conformations for the pyranoses and Haworth projections for the furanoses.

(a)αDmannopyranose(C2epimerofglucose)(b)βDgalactopyranose(C4epimerofglucose)(c)βDallopyranose(C3epimerofglucose)(d)αDarabinofuranose(e)βDribofuranose(C2epimerofarabinose)

Short Answer

Expert verified

(a)

αDmannopyranose

(b)

βDgalactopyranose

(c)

βDallopyranose

(d)

αDarabinofurinose

(e)

βDribofuranose

Step by step solution

01

Pyranose, furanose, Epimers and Anomers

Pyranose is a six-membered cyclic hemiacetal while a furanose is a five-membered cyclic hemiacetal.

Epimers are sugars with a common structure, such as the arrangement of H and OH around carbon atoms, except for the carbon present at position or carbon number 2. Glucose and mannose, for example, are epimers of each other.

Anomers are the diastereomers that result during cyclization. Only the arrangement surrounding the first carbon C1, referred known as the anomeric carbon, differs (hemiacetal carbon atom).

02

Identifying α‐and β‐  anomers of pyranoses and furanoses

For αanomer, hydroxy group (-OH) on the anomeric carbon is down (axial position) while for βanomer, hydroxy group (-OH) on the anomeric carbon is up (equatorial position). Again, for αanomer, the anomeric hydroxy(-OH) group is placed trans to the terminal -CH2OHgroup while for β anomer, the anomeric hydroxy (-OH) group is placed cis to the terminalCH2OH group.

03

Structure of monosaccharides

(a) In chair conformation of αDmannopyranose, the anomeric carbon is C1 . The hydroxy group (-OH) on the anomeric carbon is down (axial position).

αDmannopyranose

In chair conformation of βDgalactopyranose, the anomeric carbon is C1. The hydroxy group (-OH) on the anomeric carbon is up (equatorial position).

βDgalactopyranose

(c) In chair conformation of βDalllopyranose, the anomeric carbon is C1 . The hydroxy group (-OH) on the anomeric carbon is up (equatorial position).


βDallopyranase

(d) In Haworth projection of αDarabinofuranose, the anomeric carbon is C1. The hydroxy group (-OH) on the anomeric carbon is down which is trans to the terminal CH2OHgroup

αDarabinofuranose

(e) In Haworth projection of , the anomeric carbon is . The hydroxy group on the anomeric carbon is up which is cis to the terminal CH2OHgroup.


βDribofuranose

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Most popular questions from this chapter

Which of the sugars mentioned in Problem 23-53 and 23-54 are reducing sugars? Which ones undergo mutarotation?

Draw the following sugar derivatives.

  1. ethyl-β-D-glucopyranoside
  2. 2,3,4,6-tetra-O-ethyl-D-mannopyranose
  3. 1,3,6-tri-O-ethyl-D-fructofuranose
  4. Ethyl-2,3,4,6-tetra-O-methyl-β-D-galactopyranoside

The Wohl degradation, an alternative to the Ruff degradation, is nearly the reverse of the Kiliani-Fischer synthesis. The aldose carbonyl group is converted to the oxime, which is dehydrated by acetic anhydride to the nitrile (a cyanohydrin). Cyanohydrin formation is reversible, and a basic hydrolysis allows the cyanohydrin to lose HCN. Using the following sequence of reagents, give equations for the individual reaction in the Wohl degradation of D-arabinose to D-erythrose. Mechanisms are not required.

(1) hydroxylamine hydrochloride

(2) acetic anhydride

(3) OH-,H2O

H. G. Khorana won the Nobel Prize in Medicine in 1968 for developing the synthesis of DNA and RNA and for helping to unravel the genetic code. Part of the chemistry he developed was the use of selective protecting groups for the 5′ OH group of nucleosides.

The trityl ether derivative of just the 5′ OH group is obtained by reaction of the nucleoside with trityl chloride, MMT chloride, or DMT chloride and a base like Et3N. The trityl ether derivative can be removed in dilute aqueous acid. DMT derivatives hydrolyze fastest, followed by MMT derivatives, and trityl derivatives slowest.

(a) Draw the product with the trityl derivative on the 5′ oxygen.

(b) Explain why the trityl derivative is selective for the 5′ OH group. Why doesn’t it react at 2′ or 3′? (c) Why is the DMT group easiest to remove under dilute acid conditions? Why does the solution instantly turn orange when acid is added to a DMT derivative?

Without referring to the chapter, draw the chair conformation of

(a) α -D-mannopyranose (the C2 epimer of glucose).

(b) β -D-allopyranose (the C3 epimer of glucose.)

(c) α -D-galactopyranose (the C4 epimer of glucose).

(d) N-formylglucosamine, glucose with C2 oxygen atom replaced by a formylated amino group.

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