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Question. (a) Figure 23-2 shows that the degradation of D-glucose gives D-arabinose, an aldopentose. Arabinose is most stable in its furanose form. Draw D-arabinofuranose.

(b) Ribose, the C2 epimer of arabinose, is most stable in its furanose form. Draw D-ribofuranose.

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01

Haworth projections

Haworth projections are used to depict cyclic sugars. It indicates the stereochemical arrangement of groups on the ring system via up and down orientation of groups or atoms. The H and OH attachment orientation can be drawn in sugar molecules.

02

Furanose form of arabinose

(a) D-arabinofuranose is the furanose form of arabinose sugar. It is formed via hemiacetal formation, and arabinose is most stable in its furanose form, which is a five-membered cyclic form.

03

Furanose form of ribose

(b) Ribose, an aldopentose, commonly exists in furanose structure, a five-membered cyclic form. The cyclisation of ribose occurs via hemiacetal formation, which is due to an attack on the aldehyde by the carbon-4 hydroxyl to produce furanose form.

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Most popular questions from this chapter

Draw the following sugar derivatives.

  1. ethyl-ฮฒ-D-glucopyranoside
  2. 2,3,4,6-tetra-O-ethyl-D-mannopyranose
  3. 1,3,6-tri-O-ethyl-D-fructofuranose
  4. Ethyl-2,3,4,6-tetra-O-methyl-ฮฒ-D-galactopyranoside

Draw the structures of the compounds named in Problem 23-20 parts (a), (c), and (d). Allose is the C3 epimer of glucose and ribose is the C2 epimer of arabinose.

Draw the following monosaccharides, using chair conformations for the pyranoses and Haworth projections for the furanoses.

(a)ฮฑโ€Dโ€mannopyranose(C2epimerofglucose)(b)ฮฒโ€Dโ€galactopyranose(C4epimerofglucose)(c)ฮฒโ€Dโ€allopyranose(C3epimerofglucose)(d)ฮฑโ€Dโ€arabinofuranose(e)ฮฒโ€Dโ€ribofuranose(C2epimerofarabinose)

All of the rings of the four heterocyclic bases are aromatic. This is more apparent when the polar resonance forms of the amide groups are drawn, as is done for thymine at left. Redraw the hydrogen-bonded guanine-cytosine and adenine-thymine pairs shown in figure 23-24, using the polar resonance forms of the amides. Show how these forms help to explain why the hydrogen bonds involved in these pairings are particularly strong. Remember that a hydrogen bond arises between an electron-deficient hydrogen atom and electron-rich pair of nonbonding electrons.

The relative configurations of the stereoisomers of tartaric acid were established by the following synthesis:

(1) D-(+)-glyceraldehydediastereomers A and B (separated)

(2) Hydrolysis of A and B using aqueous Ba(OH)2 gave C and D, respectively.

(3) HNO3 oxidation of C and D gave (-)-tartaric acid and meso-tartaric acid, respectively.

(a) You know the absolute configuration of D-(+)-glyceraldehyde, Use Fischer projections to show the absolute configurations of products A, B, C, and D.

(b) Show the absolute configurations of the three stereoisomers of tartaric acid: (+)-tartaric acid, (-)-tartaric acid, and meso-tartaric acid.

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