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A compound of formula C11H16N2gives the IR, 1HNMR, and 13CNMR spectra shown. The proton NMR peak atδ 2.0disappears on shaking with D2O. Propose a structure for this compound, and show how your structure accounts for the observed absorptions.

Short Answer

Expert verified

The required structure is as follow.

Step by step solution

01

Structure determination information from IR spectrum:

Molecular formula C11H16N2 has five elements of unsaturation, enough for a benzene ring and no oxygens precludes nitro group and amide. If cyanide group is present then there are not enough elements of unsaturation left for a benzene ring, so benzene and cyanide group are mutually exclusive.

From IR spectrum, we can deduce that, one spike is present around 3300 cm-1 which suggests a secondary amine. No cyanide group is present. -CH and C=C regions suggest an aromatic ring.

02

Structure determination from proton and carbon NMR spectrum:

From proton NMR spectrum, -5H multiple at chemical shift value 7.3 indicates a monosubstituted benzene ring (the fact that all the peaks are huddled around 7.3 precludes nitrogen being bonded to the ring). 1H singlet at chemical shift value of 2.0 is exchangeable which indicates NH of secondary amine. 2H singlet at chemical shift value 3.5 is methylene; the fact that it is so strongly DE shielded and unsplit suggests that it is between a nitrogen and benzene ring.

So far, you have fragments as follows.

From carbon NMR spectrum, there are four signals around chemical shift values 125-138 which indicates aromatic carbons. The signal at chemical shift value 65 is the methylene bonded to the benzene. The other four carbons come as two signals at chemical shift value 46 and 55, each is a methylene carbon. So, there are two sets of two equivalent methylene groups each bonded to nitrogen atom to shift it downfield.

So far, you have fragments as follows.

There is no evidence for an alkene in any of the spectra, so the remaining element of unsaturation must be a ring. The simplicity of NMR indicates a fairly symmetric compound.

Structure determination from the given data.

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Most popular questions from this chapter

Determine which of the heterocyclic amines just shown are not aromatic. Give the reasons for your conclusions.

Macrolide antibiotics all have large rings (macrocycle) in which an ester makes the ring; a cyclic ester is termed a lactone. One example is erythromycin A, first isolated from soil bacteria in the 1950’s. Over time, some pathogenic bacteria have developed resistance to erythromycin by evolving an enzymatic mechanism to cleave the macrocycle at the ketone. To counter this resistance, chemists modified the erythromycin structure to replace the ketone with an amine that the bacteria could not detoxify. This modified antibiotic, azithromycin, trade name Zithromax®, is one of the most prescribed drugs in the world for respiratory infections.

(a) Identify the lactone group in each structure that merits the classification as macrolides.

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(e) From what you know about the reactivity of ketones and amines, why was an amine a good choice to be the “chemical opposite of a ketone”?

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