(a)Hydroboration of a terminal alkyne with disiamylborane (Sia2 BH)followed by the oxidation with hydrogen peroxide in the presence of a base results in an aldehyde. The reaction can be given as:

(b)The mechanism of the reaction can be given as:
The ethoxide ion strikes the electrophilic carbon atom of the alkyne group and generates a carbanion. The base abstracts a proton forming a trans-alkene. The double bond combines with an acid to form a carbocation. The water molecule functions as a nucleophile and strikes the carbocation to form an intermediate.
Another water molecule then abstracts a proton forming a hemiacetal. Protonation of the ether oxygen results in a good leaving group. The leaving group (ethanol) expels and leads to a resonance stabilized intermediate. The desired product is generated by the loss of hydroxyl proton.
The reaction can be given as:

(c)The closer the electrons are to the nucleus, the more stable is the molecule. An s orbital is near to the nucleus than the p orbital as the p orbitals are situated away from the nucleus. An sp2carbanion is more stable than the carbanion. The sp2carbanion has 33% s character and the electron pair is near to the positive nucleus than in the sp3 carbanion which has 25% s character. The sp2carbanion is easier to form due to its relative stability.

Formation of sp2and sp3carbanion