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Predict the product(s) you would expect from the treatment of each compound with (1) dilute, neutral and (2) warm basic , then dilute acid.

(a) hex-1-yne (b) hex-2-yne (c) hex-3-yne

(d) 2-methylhex-3-yne (e) cyclodecyne

Short Answer

Expert verified

Alkyne is oxidized using the oxidizing agent, e.g., potassium dichromate (KMnO4), by supplying nascent oxygen.

Alkyne can oxidize in acidic and basic mediums using potassium dichromate(KMnO4) reagent.

Step by step solution

01

Step 1: Oxidation of Alkyne

Alkyne is oxidized using the oxidizing agent, e.g., potassium dichromate (KMnO4), by supplying nascent oxygen.

Alkyne can oxidize in acidic and basic mediums using potassium dichromate(KMnO4) reagent.

02

Step 2: Product formed when alkyne treated with dilute, neutral KMnO4

Alkyne, when reacted with cold aqueous potassium permanganate under neutral conditions, results in the formation of - diketone while the terminal alkyne forms keto-acid.

(a) Treating hex-1-yne with dilute, neutral KMnO4forms 2-oxohexanoic acid.

(b) Treating hex-2-yne with dilute, neutral KMnO4 forms 2-oxopentanoic acid.

(c) Treating hex-3-yne with dilute, neutral KMnO4 forms hexane-3,4-dione.

(d) Treating 2-methylhex-3-yne with dilute, neutral KMnO4 forms 2-methylhexane-3,4-dione.

(e) Treating cyclodecyne with dilute, neutral KMnO4 forms cyclo-1,2-dione.

03

Product formed when alkyne is treated with warm basic KMnO4 , then dilute acid

Alkyne when react with warm basic then dilute acid forms carboxylic acid while the terminal alkyne form carboxylic acid and carbon dioxide are released out.

(a) Treating hex-1-yne with warm basic KMnO4 then dilute acid forms pentanoic acid and carbon dioxide is released out.


(b)Treating hex-2-yne with warm basic KMnO4 then dilute acid forms acetic acid and butyric acid.

(c) Treating hex-3-yne with warm basic KMnO4 then dilute acid forms two equivalent propionic acids.

(d) Treating 2-methylhex-3-yne with warm basic KMnO4 then dilute acid forms isobutyric acid and propionic acid.

Formation of isobutyric acid and propionic acid

(e) Treating cyclodecyne with warm basic KMnO4 then dilute acid forms decanedioic acid.

Formation of decanedioic acid

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Most popular questions from this chapter

Using any necessary inorganic reagents, show how you would convert acetylene and isobutylbromide to

(a)meso-2,7-dimethyloctane-4,5-diol,(CH3)2CHCH2CH(OH)CH(OH)CH2CH(CH3)2 .

(b) (ยฑ ) -2,7-dimethyloctane-4,5-diol

Show how you would convert

(a) oct-3-yne to cis-oct-3-ene.

(b) pent-2-yne to trans-pent-2-ene.

(c) cis-cyclodecene to trans-cyclodecene.

(d) but-1-yne to cis-hex-3-ene.

Question:When treated with hydrogen and a platinum catalyst, an unknown compound X absorbs 5 equivalents of hydrogen to give n-butylcyclohexane. Treatment of X with an excess of ozone, followed by dimethyl sulfide and water, gives the following products:

Propose a structure for the unknown compound X. Is there any uncertainty in your structure?

Question:The application box in the margin of page 473 states, โ€œThe addition of an acetylide ion to a carbonyl group is used in the synthesis of ethchlorvynol, a drug used to cause drowsiness and induce sleep.โ€ Show how you would accomplish this synthesis from acetylene and a carbonyl compound.

ethchlorvynol

Question:Show how you would accomplish the following synthetic transformations. Show all intermediates.

(a)2,2-dibromobutaneโ†’but-1-yne

(b)2,2-dibromobutaneโ†’but-2-yne

(c)but-1-yneโ†’oct-3-yne

(d)trans-hex-2-eneโ†’hex-2-yne

(e)2,2-dibromohexaneโ†’hex-1-yne

(f)cyclodecyneโ†’cis-cyclodecene

(g)cyclodecyneโ†’trans-cyclodecene

(h)hex-1-yneโ†’hexan-2-one, CH3COCH2CH2CH2CH3

(i)hex-1-yneโ†’hexanal, CH3(CH2)4CHO

(j)trans-hex-2-eneโ†’cis-hex-2-ene

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