Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question: Ethyllithium is often used as a base in organic reactions,

(a)Predict the products of the following acid-base reaction,

(b) What is the conjugate acid of? Would you expectto be a strong base or a weak base?

Short Answer

Expert verified

(a)

(b)

Step by step solution

01

Bronsted – Lowry concept of acid and base

According to Bronsted-Lowry, an acid can be defined as any substance (molecule or ion) that has the tendency to donate a proton(H+) to any substance whereas a base can be defined as any substance (molecule or ion) that has the tendency to accept a proton(H+) from any other substance.

02

Conjugate acid-base pair

The residual part of acid after losing a proton (H+) will have a tendency to accept a proton(H+) . Therefore, it will behave as a base. These pairs of substances which differ from one another by a proton (H+) are known as conjugate acid-base pairs. Consider a general example of an acid:

03

Prediction of the products and explanation            

(a) Bronsted-Lowry acid is a proton (H+)donor while Bronsted-Lowry base is a proton (H+)acceptor.

(b) The conjugate acid of CH3CH2Li is CH3-CH3 (or C2H6). Ethane (C2H6 )is a very weak acid because its pKa is around 50. Since it is a very weak acid therefore its conjugate base is a very strong base. Hence, CH3CH2Li can be expected to be a strong base.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free