Chapter 4: Problem 27
Draw the five cycloalkanes with the formula \(\mathrm{C}_{5} \mathrm{H}_{10}\) -
Short Answer
Expert verified
Draw cyclopentane, a methyl-substituted cyclobutane, and ethyl or dimethyl-substituted cyclopropanes.
Step by step solution
01
Understand the Cycloalkane Formula
For cycloalkanes, the general formula is \\(\mathrm{C}_n\mathrm{H}_{2n}\). Since we are given \(\mathrm{C}_5\mathrm{H}_{10}\), \it confirms that we are dealing with rings (not straight chains or alkenes). This means there will be five carbon atoms forming a ring.
02
Identify Possible Cycloalkane Structures
Since we need to draw cycloalkanes with the formula \(\mathrm{C}_5\mathrm{H}_{10}\), \we will explore different ways to form five carbon rings, including possible geometric and conformational isomers.
03
Draw Cyclopentane
The simplest cycloalkane is cyclopentane, which is a five-carbon ring with no branches or substitutions. Draw a pentagon to represent this ring.
04
Consider Methyl-Substituted Cyclobutanes
Another possibility is to have four carbon atoms in a square (cyclobutane) with a methyl group (\(\mathrm{CH}_3\)) attached to one of the carbons. Draw the square and add a methyl group as a branch.
05
Contemplate Ethyl or Dimethyl-Substituted Cyclopropanes
Similarly, you can have three carbon atoms in a triangle (cyclopropane) with two carbon atoms as substituents. This can be either an ethyl group or two methyl groups on any of the carbons in cyclopropane. Draw the triangle and add the branches accordingly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cyclopentane
Cyclopentane is one of the simplest and most fundamental cycloalkanes, made up solely of carbon and hydrogen atoms. It is comprised of a ring of five carbon atoms, each bonded to two hydrogen atoms, forming a total of ten hydrogen atoms. The structure resembles a regular pentagon, though in reality, the molecule is not perfectly planar due to the natural spatial orientations of the atoms involved.
- The formula of cyclopentane is \(\mathrm{C}_5\mathrm{H}_{10}\), ensuring its classification as a cycloalkane because it fits the general formula \(\mathrm{C}_n\mathrm{H}_{2n}\).
- Cyclopentane is notable for the fact it does not have any branches or substitutions, making it a simple and clear representation of a five-membered cyclic structure.
Methyl-Substituted Cyclobutane
Methyl-substituted cyclobutane illustrates another way to conform to the cycloalkane formula of \(\mathrm{C}_5\mathrm{H}_{10}\). In this structure, the core is a cyclobutane ring – a square made up of four carbon atoms. By adding a methyl group \((\mathrm{CH}_3)\) as a substituent to any of the carbon atoms, we keep the carbon count at five, fitting the molecular composition.
- The core cyclobutane structure contributes four carbons to the structure, while the methyl group provides the fifth carbon required.
- This type of substitution offers room for various geometric isomers, depending on which carbon the methyl group attaches to.
Cyclopropane Isomers
Cyclopropane is the smallest cycloalkane, containing only three carbon atoms linked in a triangular formation. To reach the formula \(\mathrm{C}_5\mathrm{H}_{10}\), cyclopropane must have extra groups appended to its structure, such as ethyl or dimethyl.
- An ethyl-substituted cyclopropane involves one ethyl group \((\mathrm{CH}_2\mathrm{CH}_3)\) attached to one of the carbons in the cyclopropane ring.
- Alternatively, using two methyl groups \((\mathrm{CH}_3)\) as branches can form isomeric structures if these are placed on different or the same carbon atom.