Chapter 24: Problem 54
How would you prepare the following substances from pentanoic acid? (a) Pentanamide (b) Butylamine (c) Pentylamine (d) 2-Bromopentanoic acid (e) Hexanenitrile (f) Hexylamine
Short Answer
Expert verified
Use chlorination and Hoffman degradation for amines, HVZ for bromination, and convert to nitrile via reaction with cyanide.
Step by step solution
01
Convert Pentanoic Acid to Pentanamide
Pentanamide can be prepared by converting pentanoic acid to its acid chloride using thionyl chloride (SOCl₂). Then react the pentanoyl chloride with ammonium (NH₃) to get pentanamide.
Reaction:
1. Pentanoic acid + SOCl₂ → pentanoyl chloride
2. Pentanoyl chloride + NH₃ → pentanamide
02
Convert Pentanoic Acid to Butylamine
First, use the Hoffman degradation method. Start by preparing the butylamine - this involves converting butanoic acid to its corresponding amine. Then, decarboxylate to achieve butylamine:
1. Convert butanoic acid to butanamide using NH₃, as shown in Step 1-like reaction.
2. Perform Hoffmann degradation on butanamide to get butylamine.
03
Convert Pentanoic Acid to Pentylamine
Use the same Hoffman degradation process:
1. Convert pentanoic acid to pentanamide.
2. Perform Hoffmann degradation on pentanamide using Br₂ and NaOH to isolate the primary amine, pentylamine.
04
Convert Pentanoic Acid to 2-Bromopentanoic Acid
For halogenation at the α-position, use the Hell-Volhard-Zelinsky reaction:
1. Treat pentanoic acid with PBr₃ to convert it to an acyl bromide.
2. Then use br₂ to introduce the bromine.
3. Hydrolyze the acyl bromide back to 2-bromopentanoic acid.
05
Convert Pentanoic Acid to Hexanenitrile
First convert pentanoic acid to pentanoyl chloride using SOCl₂. Then, convert the acyl chloride to a nitrile using sodium cyanide (NaCN):
1. Pentanoic acid + SOCl₂ → pentanoyl chloride
2. Pentanoyl chloride + NaCN → hexanenitrile.
06
Convert Pentanoic Acid to Hexylamine
Convert pentanoyl chloride to hexanenitrile as described in Step 5 and use the following conversion:
1. Reduce nitrile to amine using LiAlH₄.
2. This reduction gives hexylamine.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Acid Chloride Formation
Acid chloride formation is a crucial step in converting carboxylic acids into more reactive intermediates like acyl chlorides. An acyl chloride is typically synthesized by treating a carboxylic acid with thionyl chloride (\( ext{SOCl}_2 \)). This reaction replaces the hydroxyl group (-OH) of the acid with a chlorine atom, forming an acyl chloride. The general reaction is:
- Carboxylic Acid + \( ext{SOCl}_2 \) → Acyl Chloride + \( ext{SO}_2 \) + \( ext{HCl} \)
Hoffman Degradation
The Hoffman degradation is a method to convert amides into primary amines, shortening the carbon chain by one carbon atom. This reaction involves the use of bromine (\( ext{Br}_2 \)) and sodium hydroxide (\( ext{NaOH} \)):
- Amide + Br₂ + NaOH → Primary Amine + NaBr + \( ext{Na}_2 ext{CO}_3 \) + \( ext{H}_2 ext{O} \)
Hell-Volhard-Zelinsky Reaction
The Hell-Volhard-Zelinsky (HVZ) reaction is used to halogenate carboxylic acids at the alpha position. This is especially useful for incorporating halogen atoms into carboxylic acids:
- Start by converting the acid into an acyl halide using \( ext{PBr}_3 \).
- Next, treat the acyl halide with Br₂ to introduce the bromine atom to the alpha position.
- Finally, hydrolyze the acyl bromide back to the carboxylic acid form.
Amine Synthesis
Amine synthesis often involves the reduction of derivatives such as nitriles or imines. One common strategy involves the reduction of nitriles to primary amines using agents like lithium aluminum hydride (\( ext{LiAlH}_4 \)). Amine synthesis is important in forming key building blocks for pharmaceuticals and materials:
- Nitrile + \( ext{LiAlH}_4 \) → Primary Amine
Nitrile Reduction
Nitrile reduction transforms nitriles into primary amines, which broadens the utility of nitriles in synthetic chemistry. One prominent method of achieving this uses \( ext{LiAlH}_4 \), a powerful reducing agent:
- Nitrile + \( ext{LiAlH}_4 \) → Primary Amine