Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Draw structures corresponding to the following IUPAC names: (a) \(N, N\) -Dimethylaniline (b) (Cyclohexylmethyl)amine (c) \(N\) -Methylcyclohexylamine (d) (2-Methylcyclohexyl)amine (e) 3 - \((N, N\) -Dimethylamino)propanoic acid

Short Answer

Expert verified
Construct structures based on functional group placements specified in names.

Step by step solution

01

Understanding N, N-Dimethylaniline

N, N-Dimethylaniline consists of an aniline group, which is a benzene ring attached to an amine group. In this case, the nitrogen is substituted with two methyl groups (CH3). Draw a benzene ring, attach a nitrogen (amine) group, and then attach two methyl groups to the nitrogen.
02

Drawing (Cyclohexylmethyl)amine

Start with a cyclohexane ring, which is hexagonal and consists of six carbon atoms. To form cyclohexylmethylamine, attach a CH2 group (methyl) to one position of the cyclohexane ring, and then attach an NH2 group (amine) to that CH2 group.
03

Constructing N-Methylcyclohexylamine

Begin with a cyclohexane ring. Attach an NH2 group (amine) directly to one of the carbon atoms on the ring. Then, add a methyl group (CH3) to the nitrogen, creating an N-methylamine group attached to cyclohexane.
04

Drawing 2-Methylcyclohexylamine

Start with a six-carbon cyclohexane ring. Number the carbon atoms in the ring. Attach a methyl group (CH3) to the second carbon, and an NH2 group directly to the third or any single carbon if unspecified to represent the amine structure.
05

Understanding 3-(N, N-Dimethylamino)propanoic acid

This compound involves a three-carbon propane backbone. At the third carbon, attach an N,N-dimethylamino group, which has a nitrogen with two methyl groups. Finally, attach a carboxylic acid group (COOH) to the first carbon of the propane chain.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

N, N-Dimethylaniline structure
Understanding the structure of N, N-Dimethylaniline is crucial in organic chemistry, particularly in the field of aromatic compounds. N, N-Dimethylaniline is an aniline derivative. Aniline itself is a benzene ring bonded to an amine group \((\text{-NH}_2)\). In N, N-Dimethylaniline, the nitrogen atom of the amine group is bonded not only to the benzene ring but also to two methyl groups \((\text{-CH}_3)\), making it a tertiary amine. To visualize or draw this structure:
  • Start with a regular benzene ring, which is a hexagonal ring consisting of six carbon atoms, with alternating double bonds.

  • Next, attach a nitrogen atom directly to the benzene ring to form the aniline base.

  • Finally, add two methyl groups \((\text{-CH}_3)\) to the nitrogen.
This configuration imparts specific chemical properties, such as a basic nature and reactivity with electrophiles.
Cyclohexylmethylamine structure
Cyclohexylmethylamine is an intriguing amine as it combines the cyclohexane ring structure with a methylamine group attached. This structure reflects both aliphatic and aromatic properties.
  • Start with the cyclohexane ring, which is a six-carbon ring forming a stable hexagonal shape due to sp\(^3\) carbon hybridization.

  • Attach a methyl group \((\text{-CH}_2)\) to one of the carbon atoms in the cyclohexane ring.

  • Then, link an amine group \((\text{-NH}_2)\) to this methyl group. In essence, the \(\text{CH}_2\) bridge links the cyclohexane ring with the amine group.
It's a straightforward arrangement but significant in terms of chemical reactivity, impacting boiling points and solubility.
N-Methylcyclohexylamine structure
The structure of N-Methylcyclohexylamine incorporates both the cyclohexane ring and a methyl amine substitution. This structure helps to demonstrate typical secondary amine characteristics.
  • Begin with the cyclohexane ring, which should consist of six carbon atoms forming a nearly planar hexagon.

  • Directly attach an amine \((\text{-NH}_2)\) group to one of the carbons on the cyclohexane structure.

  • Add a methyl \((\text{-CH}_3)\) group to the nitrogen in the amine section-forming N-Methylated amine.
This placement and setup result in specific chemical behavior, lending insight into its solubility and interaction with other organic molecules or compounds, such as through resonance and inductive effects.
2-Methylcyclohexylamine structure
The 2-Methylcyclohexylamine structure is essential for understanding the impact of positional isomerism in cycloalkanes. This compound highlights how substitution position affects chemical properties.
  • Construct a cyclohexane ring, noting its flexibility and chair-like conformation.

  • Identify the second carbon on the ring; often, numbering starts at the most substituted carbon.

  • On this second carbon, attach a methyl group \((\text{-CH}_3)\). This reflects a positional isomer of a methylation.

  • Attach an amine group \((\text{-NH}_2)\) directly to one of the carbons in the ring, more commonly to an adjacent carbon when unspecified.
Understanding these steps is key to predicting the molecule's behavior during reactions such as substitutions or eliminations.
3-(N, N-Dimethylamino)propanoic acid structure
The chemical structure of 3-(N, N-Dimethylamino)propanoic acid involves the combination of an amino group with a carboxylic acid on a propane chain, demonstrating the multifunctionality of organic compounds.
  • Start with a straight chain of three carbon atoms to form the propane backbone.

  • On the third carbon atom, attach a nitrogen atom that is further bonded to two methyl groups \((\text{-CH}_3)\), forming the dimethylamino group.

  • Attach a carboxylic acid group \((\text{-COOH})\) to the first carbon in the chain.
Mastery of this structure reveals the interplay of acidity from the carboxylic acid and basicity from the amine, offering insight into compound behavior during proton exchange or amidation reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free