Chapter 22: Problem 53
When an optically active carboxylic acid such as \((R)-2\) -phenylpropanoic acid is brominated under Hell-Volhard-Zelinskii conditions, is the product optically active or racemic? Explain.
Short Answer
Expert verified
The product is racemic due to planar enol intermediate formation during halogenation.
Step by step solution
01
Understand the Reactants
Identify that the reactant is \((R)-2\)-phenylpropanoic acid. This molecule is optically active because it has a chiral center, which is the carbon atom attached to -COOH, -CH(CH₃), and -C₆H₅ groups.
02
Describe the Hell-Volhard-Zelinskii Reaction
In this reaction, a carboxylic acid is first converted to an acyl halide in the presence of a halogen and phosphorus tribromide (PBr₃). The acyl halide then undergoes substitution at the alpha position with a halogen (in this case, bromine).
03
Analyze the Effects on Chirality
When the alpha hydrogen of the chiral center in (R)-2-phenylpropanoic acid is substituted by a bromine atom, it goes through enolization and halogenation. Enolization results in the formation of a planar sp² hybridized enol intermediate, which leads to the loss of chirality.
04
Formation of Racemic Mixture
The bromine can add to either side of the planar enol intermediate, which results in the formation of both R and S enantiomers equally. This step produces a racemic mixture.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Optical Activity
Optical activity refers to a substance's ability to rotate the plane of polarized light. In chemistry, molecules that have this property are considered optically active. This occurs due to asymmetry in the molecule's structure.
For example, in \( (R)-2 \)-phenylpropanoic acid, the presence of a chiral center makes the molecule optically active. As polarized light passes through such a substance, the molecule twists the light to a certain degree, either to the left (levorotary) or to the right (dextrorotary).
The degree of rotation depends on the substance's concentration, the path length of the light, and the wavelength used for measurement. Therefore, molecules like \( (R)-2 \)-phenylpropanoic acid can significantly impact how polarized light behaves due to their unique structural characteristics.
For example, in \( (R)-2 \)-phenylpropanoic acid, the presence of a chiral center makes the molecule optically active. As polarized light passes through such a substance, the molecule twists the light to a certain degree, either to the left (levorotary) or to the right (dextrorotary).
The degree of rotation depends on the substance's concentration, the path length of the light, and the wavelength used for measurement. Therefore, molecules like \( (R)-2 \)-phenylpropanoic acid can significantly impact how polarized light behaves due to their unique structural characteristics.
Chiral Center
A chiral center is a carbon atom in a molecule that is bonded to four different groups. This uniqueness leads to non-superimposable mirror images, also known as enantiomers.
The presence of a chiral center is crucial for a molecule to exhibit optical activity. Consider the case of \( (R)-2 \)-phenylpropanoic acid. The chiral center in this molecule is connected to the carboxyl group, a methyl group, and a phenyl group. This unique setup allows the molecule to exist in two forms: the (R) and the (S) form, which are mirror images.
The specific configuration of these groups determines the molecule's optical activity and how it interacts with polarized light. Identifying the presence of a chiral center is essential when studying the properties and reactivity of organic molecules.
The presence of a chiral center is crucial for a molecule to exhibit optical activity. Consider the case of \( (R)-2 \)-phenylpropanoic acid. The chiral center in this molecule is connected to the carboxyl group, a methyl group, and a phenyl group. This unique setup allows the molecule to exist in two forms: the (R) and the (S) form, which are mirror images.
The specific configuration of these groups determines the molecule's optical activity and how it interacts with polarized light. Identifying the presence of a chiral center is essential when studying the properties and reactivity of organic molecules.
Racemic Mixture
A racemic mixture is a chemical mixture that contains equal amounts of two enantiomers, often denoted as (R) and (S). Racemic mixtures do not show optical activity because the effects of each enantiomer cancel out.
In the Hell-Volhard-Zelinskii reaction discussed, the final product is a racemic mixture due to the process of enolization. During enolization, the chiral center becomes part of a planar, non-chiral intermediate. This allows the bromine atom to add equally to both sides of the planar structure.
As a result, the reaction generates both (R) and (S) enantiomers in equal proportions, leading to a racemic mixture that does not rotate polarized light. Understanding the formation of racemic mixtures is crucial in reactions where stereochemistry plays a significant role.
In the Hell-Volhard-Zelinskii reaction discussed, the final product is a racemic mixture due to the process of enolization. During enolization, the chiral center becomes part of a planar, non-chiral intermediate. This allows the bromine atom to add equally to both sides of the planar structure.
As a result, the reaction generates both (R) and (S) enantiomers in equal proportions, leading to a racemic mixture that does not rotate polarized light. Understanding the formation of racemic mixtures is crucial in reactions where stereochemistry plays a significant role.
Enolization
Enolization is a chemical process where a ketone or aldehyde with an alpha hydrogen is converted into an enol, which is an alkene with a hydroxyl group attached. Enolization involves the alpha position becoming planar and sp² hybridized.
In the context of the Hell-Volhard-Zelinskii reaction, enolization leads to the loss of chirality. When the alpha hydrogen of a chiral compound is substituted, the intermediate formed is an enol that does not have a specific configuration. This sp² hybridized state allows reactions to occur on either face of the enol, making the attack by halogens, like bromine, non-selective.
This process is essential for understanding how reactions like the Hell-Volhard-Zelinskii can transform optically active compounds into non-active racemic mixtures.
In the context of the Hell-Volhard-Zelinskii reaction, enolization leads to the loss of chirality. When the alpha hydrogen of a chiral compound is substituted, the intermediate formed is an enol that does not have a specific configuration. This sp² hybridized state allows reactions to occur on either face of the enol, making the attack by halogens, like bromine, non-selective.
This process is essential for understanding how reactions like the Hell-Volhard-Zelinskii can transform optically active compounds into non-active racemic mixtures.
Stereochemistry
Stereochemistry involves the study of spatial arrangements of atoms in molecules and their effects on the physical and chemical properties. It's a key factor in determining how molecules interact with each other and external factors, such as light.
The Hell-Volhard-Zelinskii reaction, for example, affects the stereochemistry of \( (R)-2 \)-phenylpropanoic acid. As the compound undergoes the reaction, the original stereochemistry is altered due to enolization. The planar enol intermediate formed can be attacked from either side, causing a mix of enantiomers.
Understanding stereochemistry is crucial for predicting the outcomes of chemical reactions. It determines how molecules may or may not interact with biological systems, where one enantiomer can have dramatically different effects than the other. The study of stereochemistry is integral to many fields, including pharmacology and materials science.
The Hell-Volhard-Zelinskii reaction, for example, affects the stereochemistry of \( (R)-2 \)-phenylpropanoic acid. As the compound undergoes the reaction, the original stereochemistry is altered due to enolization. The planar enol intermediate formed can be attacked from either side, causing a mix of enantiomers.
Understanding stereochemistry is crucial for predicting the outcomes of chemical reactions. It determines how molecules may or may not interact with biological systems, where one enantiomer can have dramatically different effects than the other. The study of stereochemistry is integral to many fields, including pharmacology and materials science.