Chapter 19: Problem 44
Paraldehyde, a sedative and hypnotic agent, is prepared by treatment of acetaldehyde with an acidic catalyst. Propose a mechanism for the reaction.
Short Answer
Expert verified
Paraldehyde forms through the acidic-catalyzed trimerization of acetaldehyde involving protonation, nucleophilic attack, and cyclization steps.
Step by step solution
01
Protonation of Acetaldehyde
The mechanism begins with the protonation of the carbonyl oxygen of acetaldehyde by the acidic catalyst. This increases the electrophilicity of the carbonyl carbon, making it more susceptible to nucleophilic attack.
02
Nucleophilic Attack
A molecule of acetaldehyde, acting as a nucleophile, attacks the electrophilic carbonyl carbon of the protonated acetaldehyde. This step results in the formation of a hemiacetal intermediate.
03
Deprotonation
The hemiacetal intermediate undergoes deprotonation, losing a hydrogen ion (proton) which can be temporarily taken up by the acidic catalyst. This forms an alkoxide intermediate.
04
Formation of Oxocarbenium Ion
The alkoxide intermediate rearranges and, in the presence of the acidic environment, regenerates the carbonyl group by losing water to form an oxocarbenium ion.
05
Repetition and Cyclization
Steps 1-4 are repeated for two more molecules of acetaldehyde. Each cycle of nucleophilic attack and proton transfer brings another acetaldehyde into the chain, forming a linear structure which eventually cyclizes to form the six-membered ring structure of paraldehyde.
06
Stabilization of Paraldehyde
Finally, the newly formed paraldehyde can undergo additional tautomerization or stabilization steps, involving shifts of protons or resonance structures, but the main carbon framework of the trimolecular cycle remains intact.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Protonation of Acetaldehyde
In the initial step of the reaction mechanism, acetaldehyde reacts with an acidic catalyst, which adds a proton to the acetaldehyde molecule. This protonation specifically targets the oxygen atom within the carbonyl group of acetaldehyde.
- Acetaldehyde, also known as ethanal, has a highly polar carbonyl group, meaning one atom (oxygen) is far more electronegative than the other (carbon).
- By protonating the oxygen atom, the molecule's overall electronegativity increases, making the carbonyl carbon highly susceptible to nucleophilic attacks.
Hemiacetal Intermediate
Once the acetaldehyde molecule is accessible for reaction, a nucleophilic acetaldehyde molecule attacks the electrophilic carbon atom of the protonated molecule. This specific nucleophilic reaction forms a particular compound called a hemiacetal intermediate.
- The term "hemiacetal" refers to a molecule featuring an alcohol (OH) group and an alkoxide group attached to the same carbon atom.
- This intermediate is a transient structural arrangement occurring during the formation of larger complex molecules.
Nucleophilic Attack
Nucleophilic attack is a common reaction step wherein an electron-rich nucleophile targets and attacks an electron-poor electrophile, usually a positively charged ion or a polar molecule. In the acetaldehyde reaction mechanism, these nucleophilic attacks occur multiple times.
- The electron-rich acetaldehyde acts as a nucleophile, first attacking the protonated acetaldehyde's carbonyl carbon.
- This continuous attack continues through several steps to create and extend the molecular chain.
Oxocarbenium Ion Formation
The rearrangement of the hemiacetal intermediate into an oxocarbenium ion is a complex process characterized by both the reformation of a carbonyl group and the expulsion of a water molecule. This transformation aids in stabilizing and setting the groundwork for cyclization.
- Oxocarbenium ions feature a positively charged carbon, typically formed by losing a bonded water molecule.
- The acidic environment provides the necessary conditions for this rearrangement to proceed smoothly and without disruption.