Chapter 18: Problem 33
When 2 -methyl-2,5-pentanediol is treated with sulfuric acid, dehydration occurs and 2,2 -dimethyltetrahydrofuran is formed. Suggest a mechanism for this reaction. Which of the two oxygen atoms is most likely to be eliminated, and why?
Short Answer
Expert verified
The oxygen at the 2-position is eliminated due to stable carbocation formation.
Step by step solution
01
Protonation of the Hydroxyl Group
The sulfuric acid, which is a strong acid, donates a proton to one of the hydroxyl groups on 2-methyl-2,5-pentanediol, making it a good leaving group. This forms an oxonium ion.
02
Formation of a Carbocation
The protonated hydroxyl group leaves, resulting in the formation of a carbocation at the 2-position. This is a tertiary carbocation and is quite stable due to its tertiary nature.
03
Ring Closure to Form the Tetrahydrofuran
A nucleophilic attack occurs as the lone pair on the other hydroxyl group (at the 5-position) attacks the carbocation. This initiates the formation of a new bond and cyclizes the molecule, forming a five-membered ring characteristic of the tetrahydrofuran structure.
04
Deprotonation and Conversion to Tetrahydrofuran
The positive charge on the oxygen of the newly formed ring is neutralized by the loss of a proton, resulting in the formation of 2,2-dimethyltetrahydrofuran.
05
Identify Oxygen Atom Eliminated and Reason
The oxygen atom at the 2-position is eliminated because its protonation leads to a stable tertiary carbocation formation, which is favored in this dehydration mechanism.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Protonation of Hydroxyl Group
In organic chemistry, the first step in many dehydration reactions is the protonation of the hydroxyl group. This involves introducing a hydrogen ion, or proton, to an -OH group on a molecule. Using sulfuric acid, a strong acid, protons are plentiful and ready to donate. Once a hydroxyl group is protonated, it transforms into an oxonium ion, a more reactive form.
The choice of which hydroxyl group to protonate often depends on the potential stability of the resulting carbocation. In our example with 2-methyl-2,5-pentanediol, targeting the hydroxyl group at the 2-position supports the development into a tertiary carbocation. This predictability in protonation sets the stage for the rest of the reaction.
- Why is this important? Because it creates a good leaving group. With an oxonium ion at hand, the molecule becomes ready to undergo subsequent changes.
- This leaving ability is crucial for the molecule to shift towards forming a new structure, in this case, aiding in the formation of a cyclic compound.
The choice of which hydroxyl group to protonate often depends on the potential stability of the resulting carbocation. In our example with 2-methyl-2,5-pentanediol, targeting the hydroxyl group at the 2-position supports the development into a tertiary carbocation. This predictability in protonation sets the stage for the rest of the reaction.
Carbocation Formation
The role of carbocations in organic reaction mechanisms is fascinating. After protonation, the next significant step involves the formation of a carbocation. Initially, when the oxonium ion loses water, a carbocation forms. In our specific case, due to the reaction beginning at the 2-position, a tertiary carbocation emerges.
Thus, the creation of a stable carbocation is a pivotal step in the dehydration mechanism, setting the framework for further transformation and eventual ring closure.
- Tertiary carbocations are notably stable compared to primary or secondary carbocations due to the inductive effect and hyperconjugation from surrounding carbon groups.
- This stability propels the reaction forward, as more stable intermediates, like our tertiary carbocation, are preferable.
Thus, the creation of a stable carbocation is a pivotal step in the dehydration mechanism, setting the framework for further transformation and eventual ring closure.
Ring Closure
Ring closure is a particularly exciting part of this mechanism. Following carbocation formation, the reaction proceeds with an intramolecular nucleophilic attack. This occurs when the lone pair from the remaining hydroxyl group, located at the 5-position, strikes the carbocation.
The efficiency of this process depends on the proper alignment and proximity of the hydroxyl group's lone pair to the carbocation. Successfully executing this step ensures the desired ring closure necessary for forming tetrahydrofuran.
- This nucleophilic act swiftly facilitates the formation of a new C-O bond.
- The process ultimately leads to cyclization, yielding a closed ring, a structural hallmark of the tetrahydrofuran molecule.
The efficiency of this process depends on the proper alignment and proximity of the hydroxyl group's lone pair to the carbocation. Successfully executing this step ensures the desired ring closure necessary for forming tetrahydrofuran.
Tetrahydrofuran Synthesis
Tetrahydrofuran synthesis is the culmination of a series of carefully coordinated steps in the dehydration mechanism. After the ring closes, the resulting compound briefly contains a positively charged oxygen. This charge needs to be resolved to achieve a stable final product.
This stable cyclic ether structure showcases the success of the dehydration process, highlighting the strategic elimination and rearrangement steps that an effective synthesis demands.
- Deprotonation is the solution. A proton is lost from the oxonium ion, neutralizing the charge and solidifying the ring structure.
- This final adjustment perfects the molecule into 2,2-dimethyltetrahydrofuran, completing the synthesis process.
This stable cyclic ether structure showcases the success of the dehydration process, highlighting the strategic elimination and rearrangement steps that an effective synthesis demands.