Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which isomer of 1-bromo-3-isopropylcyclohexane reacts faster when refluxed with potassium tert-butoxide, the cis isomer or the trans isomer? Draw the structure of the expected product from the faster-reacting compound.

Short Answer

Expert verified
Answer: The trans isomer of 1-bromo-3-isopropylcyclohexane reacts faster with potassium tert-butoxide due to the more stable intermediate it forms. The expected product from the faster-reacting compound is 1-isopropyl-3-methylcyclohexene.

Step by step solution

01

Recall the E2 elimination mechanism

The reaction of 1-bromo-3-isopropylcyclohexane with potassium tert-butoxide (t-BuOK) will proceed via E2 elimination mechanism as it involves a strong base, t-BuOK. In an E2 elimination reaction, an alpha hydrogen (adjacent to the leaving group) is abstracted, and the leaving group (bromine) departs simultaneously to form a double bond.
02

Draw the structures of cis and trans isomers

First, draw both cis and trans isomers of 1-bromo-3-isopropylcyclohexane. In the cis isomer, the bromine and the isopropyl group are on the same side (both axial or both equatorial). In the trans isomer, the bromine and the isopropyl group are on opposite sides (one axial and one equatorial). Cis isomer: ![cis](https://i.imgur.com/RXPYWM3.png) Trans isomer: ![trans](https://i.imgur.com/Dk8SUdJ.png)
03

Compare the intermediates' stabilities

Now we need to determine the stability of the intermediates in both cis and trans isomers when t-BuOK abstracts an alpha hydrogen. The more stable intermediate leads to a faster reaction. In the cis isomer, the abstraction of the axial alpha hydrogen by t-BuOK will result in a less stable intermediate, as the axial isopropyl and t-BuO- groups will experience 1,3-diaxial steric interactions. In the trans isomer, the t-BuO- can easily abstract an equatorial alpha hydrogen, resulting in a more stable intermediate due to the lack of 1,3-diaxial steric interactions. Thus, the trans isomer will react faster.
04

Draw the structure of the expected product

For the trans isomer, the t-BuO- abstracts an equatorial alpha hydrogen, and the bromine leaves to form a double bond between carbons 1 and 2. The expected product is 1-isopropyl-3-methylcyclohexene. Here is the structure of the product: ![product](https://i.imgur.com/z5EqIWM.png)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free