Chapter 9: Problem 33
Solvolysis of the following bicyclic compound in acetic acid gives a mixture of products, two of which are shown. The leaving group is the anion of a sulfonic acid, \(\mathrm{ArSO}_{3} \mathrm{H}\). A sulfonic acid is a strong acid, and its anion, \(\mathrm{ArSO}_{3}{ }^{-}\), is a weak base and a good leaving group. Propose a mechanism for this reaction. \(\mathrm{O}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.