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In this chapter, we studied the mechanism of the acid-catalyzed hydration of an alkene. The reverse of this reaction is the acid-catalyzed dehydration of an alcohol.

Short Answer

Expert verified
Answer: The four main steps in the acid-catalyzed dehydration of an alcohol are: 1) Protonation of the alcohol, 2) Formation of a carbocation, 3) Rearrangement (if necessary), and 4) Elimination of a proton to form an alkene.

Step by step solution

01

Protonation of the alcohol

In this step, the alcohol reacts with a strong acid, like sulfuric acid (H2SO4). The oxygen atom of the alcohol (-OH) grabs a proton (H+) from the acid, forming a water molecule (H2O) and the conjugate base of the acid. The alcohol is transformed into a protonated alcohol with an OH2+ group.
02

Formation of a carbocation

Next, the protonated alcohol undergoes a heterolytic cleavage, where a water molecule is released, leaving behind a positively charged carbon atom (carbocation). The carbocation is electron-deficient, making it highly reactive and susceptible to rearrangement or reaction with a nucleophile.
03

Rearrangement (if necessary)

If possible, the carbocation may undergo a rearrangement to form a more stable carbocation through a hydride or alkyl shift. In this process, the neighboring hydrogen or alkyl group moves to the carbocation with its bonding electron pair, filling the positive charge, and creating a new, more stable, carbocation in a neighboring carbon atom. If the carbocation is already the most stable possible (for example, a tertiary carbocation), this step doesn't happen, so we can move to the next step.
04

Elimination of a proton

The carbocation reacts with the conjugate base of the acid (A-) produced in step 1 to remove a proton from an adjacent carbon, releasing an electron pair to form a double bond between the carbocation carbon and the adjacent carbon, which leads to the elimination of the positive charge. This step generates an alkene and regenerates the acid catalyst. In conclusion, the acid-catalyzed dehydration of an alcohol follows these steps: protonation, formation of a carbocation, possible rearrangement, and elimination of a proton to form an alkene.

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Most popular questions from this chapter

Draw a structural formula for the cycloalkene with the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{10}\) that reacts with \(\mathrm{Cl}_{2}\) to give each compound. (a) Cl[C]1CCCC[C]1Cl (b) CC1CC(Cl)C(Cl)C1 (c) CC1(Cl)CCCC1Cl (d) ClCC1(Cl)CCCC1

Draw a structural formula for the alcohol formed by treating each alkene with borane in tetrahydrofuran (THF) followed by hydrogen peroxide in aqueous sodium hydroxide and specify stereochemistry where appropriate. (a) C=C1CCCCC1 (b) CC1=CCCCC1 (c) CCC=C(C)C (d) C=CCCCCCC (e) C=CC(C)(C)C

Reaction of \(\alpha\)-pinene with borane followed by treatment of the resulting trialkylborane with alkaline hydrogen peroxide gives the following alcohol. Of the four possible cis,trans isomers, one is formed in over \(85 \%\) yield. (a) Draw structural formulas for the four possible cis,trans isomers of the bicyclic alcohol. (b) Which is the structure of the isomer formed in \(85 \%\) yield? How do you account for its formation? Create a model to help you make this prediction.

Account for the regioselectivity and stereoselectivity observed when 1 -methylcyclopentene is treated with each reagent. (a) \(\mathrm{BH}_{3}\) (b) \(\mathrm{Br}_{2}\) in \(\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{Hg}(\mathrm{OAc})_{2}\) in \(\mathrm{H}_{2} \mathrm{O}\)

The Diels-Alder reaction between a diene and an alkene is quite remarkable in that it is one of the few ways that chemists have to form two new carbon- carbon bonds in a single reaction. Given what you know about the relative strengths of carbon-carbon sigma and pi bonds, would you predict the Diels- Alder reaction to be exothermic or endothermic? Explain your reasoning.

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