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Treatment of cyclohexene with iodobenzene under the conditions of the Heck reaction might be expected to give 1-phenylcyclohexene. The exclusive product, however, is 3-phenylcyclohexene. Account for the formation of this product.

Short Answer

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Answer: The exclusive formation of 3-phenylcyclohexene is due to the selectivity of the migratory insertion step in the Heck reaction, which is influenced by the steric factors of the reaction. The steric hindrance at the 1-carbon position makes the formation of 1-phenylcyclohexene less favorable, favoring the formation of the 3-phenylcyclohexene product.

Step by step solution

01

Understanding the Heck reaction

The Heck reaction is a palladium-catalyzed carbon-carbon bond formation reaction between an alkene and an aryl or vinyl halide. It occurs through a series of steps involving oxidative addition, migratory insertion, and reductive elimination. The key intermediate in this reaction is the alkylpalladium complex.
02

Reaction of cyclohexene and iodobenzene under Heck reaction conditions

When cyclohexene reacts with iodobenzene under Heck reaction conditions, the first step is the oxidative addition of the iodobenzene to the palladium catalyst. This step generates an aryl palladium complex. Next, the alkene (cyclohexene) coordinates with the palladium to form a new intermediate.
03

Migratory insertion of the alkene

In this step, the carbon-carbon bond is formed by the migratory insertion of the alkene into the carbon-palladium bond. This forms a cyclic palladium-alkyl intermediate. The new carbon-carbon bond can be formed either at the 1-carbon or the 3-carbon position of the cyclohexene. Selectivity depends on the steric and electronic factors of the reaction.
04

Formation of 3-phenylcyclohexene

In the case of the given exercise, the migratory insertion occurring at the 3-carbon position is favored over the 1-carbon position. This is due to the steric hindrance faced at the 1-carbon position, making the reaction less favorable. On the other hand, the 3-carbon position faces less steric hindrance, allowing it to react more easily. This results in the formation of 3-phenylcyclohexene as the exclusive product.
05

Reductive elimination and product formation

Lastly, to complete the reaction, a reductive elimination step takes place, releasing 3-phenylcyclohexene and regenerating the palladium catalyst. In conclusion, the exclusive formation of 3-phenylcyclohexene is due to the selectivity of the migratory insertion step in the Heck reaction, which is influenced by the steric factors of the reaction. The steric hindrance at the 1-carbon position makes the formation of 1-phenylcyclohexene less favorable, favoring the formation of the 3-phenylcyclohexene product.

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Most popular questions from this chapter

Show the sequence of Heck reactions by which the following conversion takes place. Note from the molecular formula given under each structural formula that this conversion corresponds to a loss of \(\mathrm{H}\) and I from the starting material.

What sequence of reactions will produce the following product if starting with trimethylsilylacetylene and the appropriate two aryl iodides?

Vancomycin is an important antibiotic. It is isolated from the bacterium Streptomyces orientalis and functions by inhibiting bacterial mucopeptide synthesis. It is a last line of defense against the resistant Staph organisms that are now common in hospitals. In 1999, Professor Dale Boger (The Scripps Research Institute) reported a synthesis of vancomycin aglycon (aglycon = lacking a sugar) involving the following steps, among others. Compound (I) was prepared from simple starting materials by a series of steps involving forming amide bonds. (a) Suggest reasonable precursors and show how the bonds could be formed (the actual reagents used have not been introduced, but they work in a similar way to those you know). (b) Give reagents for this reaction and suggest the mechanism. One of the interesting features of this synthesis is that ring \(C\) in compound (II) (and subsequent compounds in this synthesis) has extremely hindered rotation. As a result, compound (II) exists as two atropisomers (Section 3.2) that are interconverted only at \(140^{\circ} \mathrm{C}\). (c) Show these two isomers. (II) was then converted to (III). (d) Suggest reagents to accomplish this transformation. Compound (III) was then converted to (IV). (e) Suggest reagents and the ring A fragment that could be used for this reaction. Closure of an amide link between the amine on ring A (after removal of the protecting group) and the carbomethoxy group above it led to a precursor of vancomycin. (f) Show the ring closure reaction of the deprotected free amino group and its mechanism. Another interesting feature of this synthesis is that rings \(A\) and \(B\) also form atropisomers. These can be converted into a \(3: 1\) mixture of the desired and undesired atropisomers on heating at \(120^{\circ} \mathrm{C}\). (g) Draw these atropisomers and show that only one can be converted to vancomycin. The synthesis of the aglycon was completed by functional manipulation and addition of ring \(\mathrm{E}\) by chemistry similar to that detailed earlier. Yet, another set of atropisomers (this time of ring E) was formed! However, this one was more easily equilibrated than the others; model studies had shown that the activation barrier for this set of atropisomers should be lower than that of the others.

As has been demonstrated in the text, when the starting alkene has \(\mathrm{CH}_{2}\) as its terminal group, the Heck reaction is highly stereoselective for formation of the \(E\) isomer. Here, the benzene ring is abbreviated \(\mathrm{C}_{6} \mathrm{H}_{5}\)-. Show how the mechanism proposed in the text allows you to account for this stereoselectivity.

Show how the following compound could be prepared by a Suzuki reaction.

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