Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which of the two nitrogens in pyridoxamine (a form of vitamin \(\mathbf{B}_{6}\) ) is the stronger base? Explain your reasoning.

Short Answer

Expert verified
Answer: The nitrogen in the amine group is the stronger base in pyridoxamine.

Step by step solution

01

Determine the structure of pyridoxamine

First, we need to know the structure of pyridoxamine. Pyridoxamine is a derivative of vitamin B6 and has the following structure: ![pyridoxamine](https://upload.wikimedia.org/wikipedia/commons/thumb/9/91/Pyridoxamine.svg/1920px-Pyridoxamine.svg.png) There are two nitrogen atoms present in the structure: one in the pyridine ring and one in the amine group attached to the pyridine ring.
02

Discuss the basicity of nitrogen atoms in organic molecules

In general, the basicity of nitrogen atoms in organic molecules is determined by their ability to accept a proton (H+) on their lone pair of electrons. A more basic nitrogen atom has its lone pair more available for protonation, and when protonated, it forms a more stable conjugate acid.
03

Evaluate the lone pair availability of the two nitrogen atoms

Let's analyze the availability of lone pairs of electrons on the two nitrogen atoms: 1. Nitrogen in the pyridine ring: The lone pair on this nitrogen atom is part of the aromatic ring system and conjugated with the alternating double bonds. Because it participates in resonance, it is less available for protonation. 2. Nitrogen in the amine group: The lone pair on this nitrogen atom is not involved in the resonance and does not participate in the aromatic ring system. It is more available to accept a proton. Based on the availability of lone pairs, the nitrogen in the amine group appears to be the stronger base.
04

Evaluate the stability of the conjugate acids

Now let's consider the stability of the conjugate acids formed when each nitrogen atom is protonated: 1. Protonated nitrogen in the pyridine ring: The positive charge generated on this nitrogen breaks the aromaticity of the ring system and decreases its stability. 2. Protonated nitrogen in the amine group: The positive charge is localized on the amine nitrogen, and the aromatic ring system is not disturbed, maintaining its stability. Based on the stability of the conjugate acids, the nitrogen in the amine group forms a more stable conjugate acid, making it comparatively the stronger base.
05

Conclusion

Considering both the availability of lone pair electrons for protonation and the stability of the resulting conjugate acids, we can conclude that the nitrogen in the amine group is the stronger base in pyridoxamine.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conjugate Acid Stability
Understanding the conjugate acid stability is fundamental in assessing the basicity of a molecule. When a base accepts a proton, it becomes a conjugate acid. The stability of this conjugate acid influences the base strength; the more stable the conjugate acid, the stronger its base form is.

How does this relate to pyridoxamine? When the amine nitrogen is protonated, its electrons become part of a simple stable charge distribution. However, protonating the nitrogen in the pyridine ring disrupts the ring's aromaticity, introducing instability. As a result, the conjugate acid formed from the amine nitrogen is more stable due to the lack of resonance disruption, pointing to a stronger base.
Lone Pair Availability
The lone pair availability is a key factor for nitrogen basicity in organic chemistry. Nitrogen's lone pair of electrons must be readily available for binding a proton to exhibit basic character. In pyridoxamine, while the nitrogen in the pyridine ring is conjugated with the π-system, reducing its availability, the amine nitrogen retains a free lone pair.

This difference is crucial. The lone pair on the amine nitrogen is not delocalized over the structure, making it more accessible for proton acceptance — a principal aspect of basicity. Hence, the amine nitrogen serves as a stronger base.
Pyridoxamine Structure
Examining the pyridoxamine structure provides insights into its chemistry. Pyridoxamine, a form of vitamin B6, incorporates two distinct nitrogen atoms — one part of a pyridine ring, the other in an amine group.

The structure shows the amine nitrogen bearing a lone pair of electrons that is not shared with the rest of the molecule, while the pyridine nitrogen is involved in the ring's resonance. This difference is the foundation for understanding why the amine nitrogen is more basic, reinforcing the importance of structural analysis in organic chemistry.
Resonance in Aromatic Systems
The concept of resonance in aromatic systems, like the pyridine ring in pyridoxamine, has great relevance in understanding basicity. Resonance involves delocalization of electrons across a molecule, creating a stabilizing effect on the system.

In pyridoxamine's pyridine ring, the nitrogen's involvement in resonance makes its electrons less available for bonding with a proton, reducing its basicity. This phenomenon emphasizes resonance as a fundamental principle in evaluating chemical behavior, illustrating how it directly impacts the reactivity of molecules like pyridoxamine.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The procedure of methylation of amines and thermal decomposition of quaternary ammonium hydroxides was first reported by Hofmann in 1851, but its value as a means of structure determination was not appreciated until 1881 , when he published a report of its use to determine the structure of piperidine. Following are the results obtained by Hofmann. Piperidine 1,4 -Pentadiene (a) Show that these results are consistent with the structure of piperidine (Section 23.1). (b) Propose two additional structural formulas (excluding stereoisomers) for \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{~N}\) that are also consistent with the results obtained by Hofmann.

Propose a synthesis of the local anesthetic ambucaine from 4-nitrosalicylic acid, ethylene oxide, diethylamine, and 1-bromobutane.

Methylparaben is used as a preservative in foods, beverages, and cosmetics. Provide a synthesis of this compound from toluene.

Draw the structural formula for a compound with the given molecular formula. (a) A \(2^{\circ}\) arylamine, \(\mathrm{C}_{7} \mathrm{H}_{9} \mathrm{~N}\) (b) \(\mathrm{A} \mathrm{} 3^{\circ}\) arylamine, \(\mathrm{C}_{8} \mathrm{H}_{11} \mathrm{~N}\) (c) \(\mathrm{A} \mathrm{}^{\circ}\) aliphatic amine, \(\mathrm{C}_{7} \mathrm{H}_{9} \mathrm{~N}\) (d) \(\mathrm{A}\) chiral \(1^{\circ}\) amine, \(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\) (e) A \(3^{\circ}\) heterocyclic amine, \(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{~N}\) (f) A trisubstituted \(1^{\circ}\) arylamine, \(\mathrm{C}_{9} \mathrm{H}_{13} \mathrm{~N}\) (g) A chiral quaternary ammonium salt, \(\mathrm{C}_{6} \mathrm{H}_{16} \mathrm{NCl}\)

Following is a retrosynthesis for the coronary vasodilator ganglefene. CC(C)(C)COC(=O)C(C)(C)C CC(C)COc1ccc(C(=O)O)cc1 CCN(CC)CC(C)C(C)O O=C(O)c1ccc(O)cc1 C=C(C)C(C)=O 4-Hydroxybenzoic acid 3-Methyl-3-buten-2-one (a) Propose a synthesis for ganglefene from 4-hydroxybenzoic acid and 3-methyl-3-buten-2-one. (b) Is ganglefene chiral? If so, which of the possible stereoisomers are formed in this synthesis?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free