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Following are structural formulas and heats of combustion of acetaldehyde and ethylene oxide. Which of these compounds is more stable? Explain. CC=O C1CO1 Acetaldehyde Ethylene oxide \(-1164 \mathrm{~kJ}(-278.8 \mathrm{kcal}) / \mathrm{mol}\) \(-1264 \mathrm{~kJ}(-302.1 \mathrm{kcal}) / \mathrm{mol}\)

Short Answer

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Answer: Acetaldehyde is more stable than ethylene oxide.

Step by step solution

01

Identify the given information

The given information in this exercise are the structural formulas and heats of combustion for acetaldehyde and ethylene oxide. Acetaldehyde has a heat of combustion of \(-1164 \mathrm{~kJ/mol}\), while ethylene oxide has a heat of combustion of \(-1264 \mathrm{~kJ/mol}\).
02

Compare the heats of combustion

We need to compare the heats of combustion of both compounds to determine which one is more stable. Acetaldehyde has a heat of combustion of \(-1164 \mathrm{~kJ/mol}\), whereas ethylene oxide has a heat of combustion of \(-1264 \mathrm{~kJ/mol}\). Since the heat of combustion of acetaldehyde is less negative than that of ethylene oxide, it means that acetaldehyde has a lower energy content and is more stable.
03

Conclusion

Based on the comparison of heats of combustion, acetaldehyde is more stable than ethylene oxide as it has a lower energy content (heat of combustion is less negative).

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Most popular questions from this chapter

Following are structural formulas for 1,4 -dioxane and piperidine. 1,4-Dioxane is a widely used solvent for organic compounds. Piperidine is found in small amounts in black pepper (Piper nigrum).

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