Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

How many different staggered conformations are there for 2-methylpropane? How many different eclipsed conformations are there?

Short Answer

Expert verified
Short Answer: In 2-methylpropane, there are 3 different staggered conformations and 3 different eclipsed conformations.

Step by step solution

01

Understand the structure of 2-methylpropane

2-methylpropane is an organic compound which contains four carbon atoms and ten hydrogen atoms. It is an isomer of butane. In 2-methylpropane, there are three carbons in the main chain and one side chain (methyl group) on the second carbon. Considering the main carbon-carbon bond between central carbon and the methyl group as C1-C2 bond, we need to rotate around this bond to determine the different conformations.
02

Determine the possible staggered conformations

To find the possible staggered conformations, we need to consider the dihedral angle between the front and back carbon atoms in the Newman projection. For staggered conformations, the dihedral angles should be 60, 180, and 300 degrees. In a Newman projection, let's place the large substituent at the front (i.e., methyl group attached to C1) at the top position as a reference. Here are the possible staggered conformations: 1. First staggered conformation: Methyl group (C2) is at the bottom of C1 (60° dihedral angle). 2. Second staggered conformation: The eclipsed conformation (C2) goes to the bottom C1 position (dihedral angle of 180°). Since both front and back positions have large substituents (methyl groups), this conformation is also a gauche conformation. 3. Third staggered conformation: The staggered conformation again, with C2 at the bottom right of C1 (dihedral angle of 300°). So, there are \boxed{3} different staggered conformations for 2-methylpropane.
03

Determine the possible eclipsed conformations

For eclipsed conformations, the dihedral angle between front and back carbon atoms in the Newman projection is 0, 120, and 240 degrees. Following the same method as in step 2, we place the large front substituent as a reference point in each case. 1. First eclipsed conformation: C2 at the top position overlapping with the C1 methyl group (dihedral angle of 0°). 2. Second eclipsed conformation: C2 at the middle right position of C1 (dihedral angle of 120°). 3. Third eclipsed conformation: C2 at the middle left position of C1 (dihedral angle of 240°). So, there are \boxed{3} different eclipsed conformations for 2-methylpropane.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain why each is an incorrect IUPAC name and write the correct IUPAC name for the intended compound. (a) 1,3 Dimethylbutane (b) 4 Methylpentane (c) 2,2-Diethylbutane (d) 2-Ethyl-3-methylpentane (e) 2-Propylpentane (f) 2,2 -Diethylheptane (g) 2,2-Dimethylcyclopropane (h) 1-Ethyl-5-methylcyclohexane

\(1,2,3,4,5,6\)-Hexachlorocyclohexane shows cis,trans isomerism. At one time, a crude mixture of these isomers was sold as an insecticide. The insecticidal properties of the mixture arise from one isomer, known as lindane, which is cis-1,2,4,5-trans3,6-hexachlorocyclohexane. (a) Draw a structural formula for \(1,2,3,4,5,6\)-hexachlorocyclohexane disregarding, for the moment, the existence of cis, trans isomerism. What is the molecular formula of this compound? (b) Using a planar hexagon representation for the cyclohexane ring, draw a structural formula for lindane. (c) Draw a chair conformation for lindane and label which chlorine atoms are axial and which are equatorial. (d) Draw the alternative chair conformation of lindane and again label which chlorine atoms are axial and which are equatorial. (e) Which of the alternative chair conformations of lindane is more stable? Explain.

Assume for the purposes of this problem that to be an alcohol (-ol) or an amine (-amine), the hydroxyl or amino group must be bonded to a tetrahedral ( \(s p^{3}\) hybridized) carbon atom. Write the structural formula of a compound with an unbranched chain of four carbon atoms that is an: (a) Alkane (d) Alkanol (b) Alkene (c) Alkyne (g) Alkanamine (e) Alkenol (f) Alkynol (j) Alkanal (h) Alkenamine (i) Alkynamine (m) Alkanone (k) Alkenal (l) Alkynal (p) Alkanoic acid (n) Alkenone (o) Alkynone (q) Alkenoic acid (r) Alkynoic acid

Consider 1-bromo-2-methylpropane and draw the following. (a) The staggered conformation(s) of lowest energy (b) The staggered conformation(s) of highest energy

When cyclohexane is substituted by an ethynyl group, \(-\mathrm{C} \equiv \mathrm{CH}\), the energy difference between axial and equatorial conformations is only \(1.7 \mathrm{~kJ}(0.41 \mathrm{kcal}) / \mathrm{mol}\). Compare the conformational equilibrium for methylcyclohexane with that for ethynylcyclohexane and account for the difference between the two.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free