Question

Write molecular formulas for the five possible molecular ions of \(\mathrm{m} / z 88\) containing the elements \(\mathrm{C}, \mathrm{H}, \mathrm{N}\), and \(\mathrm{O}\).

Short answer

Question: List the five possible molecular ions with a mass-to-charge ratio (m/z) of 88, containing the elements Carbon (C), Hydrogen (H), Nitrogen (N), and Oxygen (O). Answer: The five possible molecular ions are: 1. C₂h 10 N 2. C6H6N2 3. C4H2N4 4. C5ON 5. C4N2O

Step-by-step solution

The atomic masses of the given elements are as follows: Carbon (C) - 12 Hydrogen (H) - 1 Nitrogen (N) - 14 Oxygen (O) - 16 #Step 2: Calculate possible combinations of elements#

Now, we'll explore the possible combinations of these elements that can add up to 88 in terms of their masses: 1. Seven Carbon atoms, One Nitrogen atom, and Ten Hydrogen atoms Total mass = 7(12) + 1(14) + 10(1) = 84 + 14 + 10 = 88 Molecular formula: \(\mathrm{C_7H_{10}N}\) 2. Six Carbon atoms, Two Nitrogen atoms, and Six Hydrogen atoms Total mass = 6(12) + 2(14) + 6(1) = 72 + 28 + 6 = 88 Molecular formula: \(\mathrm{C_6H_6N_2}\) 3. Four Carbon atoms, Four Nitrogen atoms, and Two Hydrogen atoms Total mass = 4(12) + 4(14) + 2(1) = 48 + 56 + 2 = 88 Molecular formula: \(\mathrm{C_4H_2N_4}\) 4. Five Carbon atoms, One Nitrogen atom, and One Oxygen atom Total mass = 5(12) + 1(14) + 1(16) = 60 + 14 + 16 = 88 Molecular formula: \(\mathrm{C_5ON}\) 5. Four Carbon atoms, Two Nitrogen atoms, and One Oxygen atom Total mass = 4(12) + 2(14) + 1(16) = 48 + 28 + 16 = 88 Molecular formula: \(\mathrm{C_4N_2O}\) These are the five possible molecular ions of m/z 88 containing the elements Carbon (C), Hydrogen (H), Nitrogen (N), and Oxygen (O): 1. \(\mathrm{C_7H_{10}N}\) 2. \(\mathrm{C_6H_6N_2}\) 3. \(\mathrm{C_4H_2N_4}\) 4. \(\mathrm{C_5ON}\) 5. \(\mathrm{C_4N_2O}\)