Chapter 13: Problem 14
Following are structural formulas, dipole moments, and \({ }^{1}\) H-NMR chemical shifts for acetonitrile, fluoromethane, and chloromethane. $$ \begin{array}{|ccc|} \hline \mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N} & \mathrm{CH}_{3} \mathrm{~F} & \mathrm{CH}_{3} \mathrm{Cl} \\ \hline \text { Acetonitrile } & \text { Fluoromethane } & \text { Chloromethane } \\ \hline 3.92 \mathrm{D} & 1.85 \mathrm{D} & 1.87 \mathrm{D} \\ \hline \delta 1.97 & \delta 4.26 & \delta 3.05 \\ \hline \end{array} $$ (a) How do you account for the fact that the dipole moments of fluoromethane and chloromethane are almost identical even though fluorine is considerably more electronegative than chlorine? (b) How do you account for the fact that the dipole moment of acetonitrile is considerably greater than that of either fluoromethane or chloromethane? (c) How do you account for the fact that the chemical shift of the methyl hydrogens in acetonitrile is considerably less than that for either fluoromethane or chloromethane?
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