Chapter 1: Problem 34
Why does fluorine, the element in the upper right corner of the Periodic Table, have the largest electronegativity of any element?
Chapter 1: Problem 34
Why does fluorine, the element in the upper right corner of the Periodic Table, have the largest electronegativity of any element?
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Get started for free(a) Draw a Lewis structure for the ozone molecule, \(\mathrm{O}_{3}\). (The order of atom attachment is \(\mathrm{O}-\mathrm{O}-\mathrm{O}\), and they do not form a ring.) Chemists use ozone to cleave carbon-carbon double bonds (Section 6.5C). (b) Draw four contributing resonance structures; include formal charges. (c) How does the resonance model account for the fact that the length of each \(\mathrm{O}-\mathrm{O}\) bond in ozone \((128 \mathrm{pm})\) is shorter than the \(\mathrm{O}-\mathrm{O}\) single bond in hydrogen peroxide \((\mathrm{HOOH}\), \(147 \mathrm{pm}\) ) but longer than the \(\mathrm{O}-\mathrm{O}\) double bond in the oxygen molecule ( \(123 \mathrm{pm})\) ?
Phosphorus is immediately under nitrogen in the Periodic Table. Predict the molecular formula for phosphine, the compound formed by phosphorus and hydrogen. Predict the \(\mathrm{H}-\mathrm{P}-\mathrm{H}\) bond angle in phosphine.
Define valence shell and valence electron.
Tetrafluoroethylene, \(\mathrm{C}_{2} \mathrm{~F}_{4}\) is the starting material for the synthesis of the polymer polytetrafluoroethylene (PTFE), one form of which is known as Teflon. Tetrafluoroethylene has a dipole moment of zero. Propose a structural formula for this molecule.
Why are the following molecular formulas impossible? (a) \(\mathrm{CH}_{5}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{7}\)
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