Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write a mechanism for the polymerization of methyl vinyl ether initiated by 2-chloro2-phenylpropane and \(\mathrm{SnCl}_{4}\). Label the initiation, propagation, and termination steps.

Short Answer

Expert verified
Question: Outline the step-by-step mechanism for the polymerization of methyl vinyl ether initiated by 2-chloro-2-phenylpropane and \(\mathrm{SnCl}_{4}\). Answer: The mechanism for the polymerization of methyl vinyl ether initiated by 2-chloro-2-phenylpropane and \(\mathrm{SnCl}_{4}\) consists of three main steps: initiation, propagation, and termination. In initiation, the carbocation is formed by reacting the initiator with the catalyst, which then reacts with the monomer to create a new carbocation. In propagation, this new carbocation reacts with another monomer to grow the polymer chain. Termination involves the end of the polymerization process, either through the reaction of the propagating carbocation with a counterion or between two carbocations to form a stable product.

Step by step solution

01

Initiation

The initiation step begins with the reaction between the initiator, 2-chloro-2-phenylpropane, and the catalyst, \(\mathrm{SnCl}_{4}\). This leads to the formation of a carbocation and a \(\mathrm{SnCl}_{3}^{-}\) ion. The carbocation will then react with the methyl vinyl ether monomer to form a new reactive species (another carbocation) that will be involved in the propagation. The initiation step can be outlined as follows: 1. 2-chloro-2-phenylpropane + \(\mathrm{SnCl}_{4}\) → carbocation + \(\mathrm{SnCl}_{3}^{-}\) 2. Carbocation + methyl vinyl ether → new carbocation
02

Propagation

The propagation step involves the reaction of the carbocation formed in the initiation step with another methyl vinyl ether monomer. This will create a longer chain with an unsaturated carbon and will generate a new carbocation that can continue reacting with more monomers. This step is repeated multiple times, leading to the growth of the polymer chain. The propagation step can be represented as: 1. New carbocation + methyl vinyl ether → longer chain carbocation 2. Repeat step with more monomers to grow the polymer chain
03

Termination

The termination step involves the end of the polymerization process. This can occur through various mechanisms, such as the reaction between the propagating carbocation and a counterion (e.g., \(\mathrm{SnCl}_{3}^{-}\)) or between two carbocations to form a stable product. The termination step can be illustrated as follows: 1. Longer chain carbocation + counterion (e.g., \(\mathrm{SnCl}_{3}^{-}\)) → end of polymerization process (stable polymer product) 2. Longer chain carbocation A + longer chain carbocation B → end of polymerization process (stable polymer product) By illustrating the initiation, propagation, and termination steps, we have described the mechanism of the polymerization of methyl vinyl ether initiated by 2-chloro2-phenylpropane and \(\mathrm{SnCl}_{4}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Polycarbonates (Section 29.5C) are also formed by using a nucleophilic aromatic substitution route (Section 22.3B) involving aromatic difluoro monomers and carbonate ion. Propose a mechanism for this reaction.

Following is the structural formula of a section of polypropylene derived from three units of propylene monomer. Draw structural formulas for comparable sections of the following. (a) Poly(vinyl chloride) (b) Polytetrafluoroethylene (c) Poly(methyl methacrylate) (d) Poly \((1,1\)-dichloroethylene)

Caprolactam, the monomer from which nylon 6 is synthesized, is prepared from cyclohexanone in two steps. In Step 1, cyclohexanone is treated with hydroxylamine to form cyclohexanone oxime. Treatment of the oxime with concentrated sulfuric acid in Step 2 gives caprolactam by a reaction called a Beckmann rearrangement. Propose a mechanism for the conversion of cyclohexanone oxime to caprolactam.

Polymerization of 2 -chloro-1,3-butadiene under Ziegler-Natta conditions gives a synthetic elastomer called neoprene. All carbon-carbon double bonds in the polymer chain have the trans configuration. Draw the repeat unit in neoprene.

When equal molar amounts of phthalic anhydride and 1,2,3-propanetriol are heated, they form an amorphous polyester. Under these conditions, polymerization is regioselective for the primary hydroxyl groups of the triol. (a) Draw a structural formula for the repeat unit of this polyester. (b) Account for the regioselective reaction with the primary hydroxyl groups only.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free