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Show how to convert toluene to 3 -hydroxybenzoic acid using the same set of reactions as in Example \(23.12\) but changing the order in which two or more of the steps are carried out.

Short Answer

Expert verified
Question: Describe the sequence of reactions needed to convert toluene to 3-hydroxybenzoic acid. Answer: To convert toluene to 3-hydroxybenzoic acid, the following sequence of reactions should be performed: 1. Nitration of toluene to produce 2-nitrotoluene. 2. Reduction of 2-nitrotoluene to ortho-toluidine. 3. Acylation of ortho-toluidine to form N-acetyl-o-toluidine. 4. Bromination of N-acetyl-o-toluidine to obtain 3-bromo-N-acetyl-o-toluidine. 5. Hydrolysis of 3-bromo-N-acetyl-o-toluidine to produce 3-hydroxybenzoic acid.

Step by step solution

01

Nitration of Toluene

First, we will perform the nitration of toluene using a mixture of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4). This reaction will lead to the formation of 2-nitrotoluene as the major product, with the nitro group at the ortho position. Toluene + HNO3 + H2SO4 -> 2-Nitrotoluene
02

Reduction of 2-Nitrotoluene

In the second step, we will reduce the nitro group in 2-nitrotoluene to an amine group using a reducing agent like tin (Sn) and hydrochloric acid (HCl). This reaction will produce ortho-toluidine as the product. 2-Nitrotoluene + Sn + HCl -> ortho-Toluidine
03

Acylation of ortho-Toluidine

Next, we will perform acylation on ortho-toluidine by reacting it with acetyl chloride (CH3COCl) in the presence of pyridine as a base. This reaction will introduce an acetyl group to the amine, forming N-acetyl-o-toluidine. ortho-Toluidine + CH3COCl + Pyridine -> N-acetyl-o-toluidine
04

Bromination of N-acetyl-o-toluidine

In order to introduce the hydroxyl group, we need to brominate N-acetyl-o-toluidine first. This is done by reacting it with bromine (Br2) in the presence of an iron (III) bromide (FeBr3) catalyst. The major product from this reaction will be 3-bromo-N-acetyl-o-toluidine. N-acetyl-o-toluidine + Br2 + FeBr3 -> 3-Bromo-N-acetyl-o-toluidine
05

Hydrolysis of 3-Bromo-N-acetyl-o-toluidine

Finally, hydrolyze 3-bromo-N-acetyl-o-toluidine using a strong base such as sodium hydroxide (NaOH). This reaction will remove the acetyl group and replace the bromine with a hydroxyl group, resulting in the formation of 3-hydroxybenzoic acid. 3-Bromo-N-acetyl-o-toluidine + NaOH -> 3-Hydroxybenzoic acid Thus, changing the order of the steps followed in Example 23.12, we successfully converted toluene to 3-hydroxybenzoic acid.

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Most popular questions from this chapter

Draw the structural formula for a compound with the given molecular formula. (a) \(\mathrm{A} 2^{\circ}\) arylamine, \(\mathrm{C}_{7} \mathrm{H}_{9} \mathrm{~N}\) (b) \(\mathrm{A} 3^{\circ}\) arylamine, \(\mathrm{C}_{8} \mathrm{H}_{11} \mathrm{~N}\) (c) \(\mathrm{A} \mathrm{}^{\circ}\) aliphatic amine, \(\mathrm{C}_{7} \mathrm{H}_{9} \mathrm{~N}\) (d) A chiral \(1^{\circ}\) amine, \(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\) (e) \(\mathrm{A} \mathrm{} 3^{\circ}\) heterocyclic amine, \(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{~N}\) (f) A trisubstituted \(1^{\circ}\) arylamine, \(\mathrm{C}_{9} \mathrm{H}_{13} \mathrm{~N}\) (g) A chiral quaternary ammonium salt, \(\mathrm{C}_{6} \mathrm{H}_{16} \mathrm{NCl}\)

Write structural formulas for these amines. (a) 2 -Methyl-1-propanamine (b) Cyclohexanamine (c) \((R)-2\)-Butanamine

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Propose steps for the following conversions using a reaction of a diazonium salt in at least one step of each conversion. (a) Toluene to 4 -methylphenol ( \(p\)-cresol) (b) Nitrobenzene to 3 -bromophenol (c) Toluene to \(p\)-cyanobenzoic acid (d) Phenol to \(p\)-iodoanisole (e) Acetanilide to \(p\)-aminobenzylamine (f) Toluene to 4 -fluorobenzoic acid (g) 3 -Methylaniline ( \(m\)-toluidine) to \(2,4,6\)-tribromobenzoic acid

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