Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The insecticide DDT is prepared by the following route. Suggest a mechanism for this reaction. The abbreviation DDT is derived from the common name dichlorodiphenyltrichloroethane.

Short Answer

Expert verified
Answer: The three main steps in the reaction mechanism for the synthesis of DDT are nucleophilic addition, elimination, and electrophilic aromatic substitution. The precursor molecules used are chloral (CCl3CHO) and chlorobenzene (C6H5Cl).

Step by step solution

01

Identify the precursor molecules and the target molecule structure

Firstly, study the structure of DDT (dichlorodiphenyltrichloroethane), and observe that it contains two phenyl rings, a central ethane moiety, and five chlorine atoms. Notice that both phenyl rings are linked to the central ethane moiety, and the ethane moiety has three chlorine atoms attached to it. Based on the structure of DDT, we can identify two precursor molecules, chloral (CCl3CHO) and chlorobenzene (C6H5Cl).
02

Determine the reaction mechanism

Now that we have identified the precursor molecules, we can determine the sequence of steps that leads to the formation of DDT: 1. Nucleophilic addition reaction: The oxygen atom of chloral (CCl3CHO) acts as a nucleophile and attacks the carbon atom of chlorobenzene (C6H5Cl), resulting in the formation of a C-O bond and the release of a chloride ion (Cl⁻). - Equation: CCl3CHO + C6H5Cl -> \textrm{Intermediate 1} 2. Elimination reaction: The oxygen atom in Intermediate 1 is protonated, which results in the formation of an O-H bond, and the cleavage of the C=O bond. This proceeds via an E2 elimination mechanism, whereby the protonated oxygen atom acts as a leaving group, taking its bonding electrons with it and forming a water molecule. This step results in the formation of a C=C bond at the central ethane moiety. - Equation: \textrm{Intermediate 1} + H^+ -> \textrm{Intermediate 2} + H2O 3. Electrophilic aromatic substitution: Chlorobenzene (C6H5Cl) reacts with Intermediate 2, in which the carbon atom of the C=C bond acts as the electrophile, and the chlorobenzene acts as a nucleophile. The electrophilic carbon atom replaces one of the hydrogen atoms on the phenyl ring by a substitution reaction. This results in the formation of DDT. - Equation: \textrm{Intermediate 2} + C6H5Cl -> DDT + HCl In summary, the mechanism for the synthesis of DDT involves nucleophilic addition, elimination, and electrophilic aromatic substitution reactions. The precursor molecules chloral and chlorobenzene are key reactants in this process.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In \(\mathrm{S}_{\mathrm{N}} 2\) reactions of alkyl halides, the order of reactivity is \(\mathrm{RI}>\mathrm{RBr}>\mathrm{RCl}>\mathrm{RF}\). Alkyl iodides are considerably more reactive than alkyl fluorides, often by factors as great as \(10^{6}\). All 1-halo-2,4-dinitrobenzenes, however, react at approximately the same rate in nucleophilic aromatic substitutions. Account for this difference in relative reactivities.

Starting with benzene, toluene, or phenol as the only sources of aromatic rings, show how to synthesize the following. Assume in all syntheses that mixtures of ortho-para products can be separated into the desired isomer. (a) 1-Bromo-3-nitrobenzene (b) 1 -Bromo-4-nitrobenzene (c) \(2,4,6\)-Trinitrotoluene (TNT) (d) \(m\)-Chlorobenzoic acid (e) \(p\)-Chlorobenzoic acid (f) \(p\)-Dichlorobenzene (g) \(m\)-Nitrobenzenesulfonic acid

Pyridine undergoes electrophilic aromatic substitution preferentially at the 3 position as illustrated by the synthesis of 3 -nitropyridine. Under these acidic conditions, the species undergoing nitration is not pyridine, but its conjugate acid. Write resonance contributing structures for the intermediate formed by attack of \(\mathrm{NO}_{2}^{+}\)at the 2,3 , and 4 positions of the conjugate acid of pyridine. From examination of these intermediates, offer an explanation for preferential nitration at the 3 position.

Show how to convert toluene to (a) 2,4 -dinitrobenzoic acid and (b) 3,5 -dinitrobenzoic acid.

Write the stepwise mechanism for sulfonation of benzene by hot, concentrated sulfuric acid. In this reaction, the electrophile is \(\mathrm{SO}_{3}\) formed as shown in the following equation. $$ \mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons \mathrm{SO}_{3}+\mathrm{H}_{2} \mathrm{O} $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free