Chapter 22: Problem 24
The insecticide DDT is prepared by the following route. Suggest a mechanism for this reaction. The abbreviation DDT is derived from the common name dichlorodiphenyltrichloroethane.
Chapter 22: Problem 24
The insecticide DDT is prepared by the following route. Suggest a mechanism for this reaction. The abbreviation DDT is derived from the common name dichlorodiphenyltrichloroethane.
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Get started for freeIn \(\mathrm{S}_{\mathrm{N}} 2\) reactions of alkyl halides, the order of reactivity is \(\mathrm{RI}>\mathrm{RBr}>\mathrm{RCl}>\mathrm{RF}\). Alkyl iodides are considerably more reactive than alkyl fluorides, often by factors as great as \(10^{6}\). All 1-halo-2,4-dinitrobenzenes, however, react at approximately the same rate in nucleophilic aromatic substitutions. Account for this difference in relative reactivities.
Starting with benzene, toluene, or phenol as the only sources of aromatic rings, show how to synthesize the following. Assume in all syntheses that mixtures of ortho-para products can be separated into the desired isomer. (a) 1-Bromo-3-nitrobenzene (b) 1 -Bromo-4-nitrobenzene (c) \(2,4,6\)-Trinitrotoluene (TNT) (d) \(m\)-Chlorobenzoic acid (e) \(p\)-Chlorobenzoic acid (f) \(p\)-Dichlorobenzene (g) \(m\)-Nitrobenzenesulfonic acid
Pyridine undergoes electrophilic aromatic substitution preferentially at the 3 position as illustrated by the synthesis of 3 -nitropyridine. Under these acidic conditions, the species undergoing nitration is not pyridine, but its conjugate acid. Write resonance contributing structures for the intermediate formed by attack of \(\mathrm{NO}_{2}^{+}\)at the 2,3 , and 4 positions of the conjugate acid of pyridine. From examination of these intermediates, offer an explanation for preferential nitration at the 3 position.
Show how to convert toluene to (a) 2,4 -dinitrobenzoic acid and (b) 3,5 -dinitrobenzoic acid.
Write the stepwise mechanism for sulfonation of benzene by hot, concentrated sulfuric acid. In this reaction, the electrophile is \(\mathrm{SO}_{3}\) formed as shown in the following equation. $$ \mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons \mathrm{SO}_{3}+\mathrm{H}_{2} \mathrm{O} $$
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