In a series of seven steps, (S)-malic acid is converted to the bromoepoxide
shown on the right in \(50 \%\) overall yield. This synthesis is
enantioselective-of the stereoisomers possible for the bromoepoxide, only one
is formed.
In thinking about the chemistry of these steps, you will want to review the
use of dihydropyran as an - OH protecting group (Section 16.7D) and the use of
the \(p\)-toluenesulfonyl chloride to convert the \(-\mathrm{OH}\), a poor leaving
group, into a tosylate, a good leaving group (Section 10.5D).
(a) Propose structural formulas for intermediates \(\mathrm{A}\) through
\(\mathrm{F}\) and specify the configuration at each chiral center.
(b) What is the configuration of the chiral center in the bromoepoxide? How do
you account for the stereoselectivity of this seven-step conversion?