Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Treating choline with acetic anhydride gives acetylcholine, a neurotransmitter. Write an equation for the formation of acetylcholine. $$ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{OH} $$ Choline

Short Answer

Expert verified
Answer: The balanced chemical equation for the formation of acetylcholine from choline and acetic anhydride is: $$ (\mathrm{CH}_{3})_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{OH} + \mathrm{CH}_{3}\mathrm{CO}\mathrm{O}\mathrm{CO}\mathrm{CH}_{3} \rightarrow \left(\mathrm{CH}_{3}\right)_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{O}\mathrm{CO}\mathrm{CH}_{3} + \mathrm{CH}_{3}\mathrm{COOH} $$

Step by step solution

01

Identify the structures of choline and acetic anhydride

Choline has the following structure: $$ (\mathrm{CH}_{3})_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{OH} $$ And acetic anhydride has the following structure: $$ \mathrm{CH}_{3}\mathrm{CO}\mathrm{O}\mathrm{CO}\mathrm{CH}_{3} $$
02

Understand the formation of acetylcholine

In the presence of choline and acetic anhydride, an acetyl group from acetic anhydride reacts with the hydroxyl group of choline to form an ester bond, producing acetylcholine and acetic acid as products. Acetylcholine has the following structure: $$ \left(\mathrm{CH}_{3}\right)_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{O}\mathrm{CO}\mathrm{CH}_{3} $$ While acetic acid has the following structure: $$ \mathrm{CH}_{3}\mathrm{COOH} $$
03

Write the balanced chemical equation

Now that we understand the reaction between choline and acetic anhydride, we can write the balanced chemical equation showing the formation of acetylcholine, as follows: $$ (\mathrm{CH}_{3})_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{OH} + \mathrm{CH}_{3}\mathrm{CO}\mathrm{O}\mathrm{CO}\mathrm{CH}_{3} \rightarrow \left(\mathrm{CH}_{3}\right)_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{O}\mathrm{CO}\mathrm{CH}_{3} + \mathrm{CH}_{3}\mathrm{COOH} $$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using your roadmaps as a guide, show how to convert 1-bromopentane and sodium cyanide into \(N\)-hexylhexanamide. You must use 1-bromopentane and sodium cyanide as the source of all carbon atoms in the target molecule. Show all reagents and all molecules synthesized along the way.

The mechanism for hydrolysis of an ester in aqueous acid involves formation of a tetrahedral carbonyl addition intermediate. Evidence in support of this mechanism comes from an experiment designed by Myron Bender. He first prepared ethyl benzoate enriched with oxygen-18 in the carbonyl oxygen and then carried out acid-catalyzed hydrolysis of the ester in water containing no enrichment in oxygen-18. If he stopped the experiment after only partial hydrolysis and isolated the remaining ester, the recovered ethyl benzoate lost a portion of its enrichment in oxygen-18. In other words, some exchange had occurred between oxygen-18 of the ester and oxygen-16 of water. Show how this observation bears on the formation of a tetrahedral carbonyl addition intermediate during acid-catalyzed ester hydrolysis.

Following is a retrosynthetic analysis for the synthesis of the herbicide (S)-Metolachlor from 2-ethyl-6-methylaniline, chloroacetic acid, acetone, and methanol. Show reagents and experimental conditions for the synthesis of Metolachlor from these four organic starting materials. Your synthesis will most likely give a racemic mixture. The chiral catalyst used by Novartis for reduction in Step 2 gives \(80 \%\) enantiomeric excess of the \(S\) enantiomer.

Reaction of a primary or secondary amine with diethyl carbonate under controlled conditions gives a carbamic ester. CCOC(=O)OCC CCCCCN CCOC(=O)NCCCF Diethyl carbonate Butylamine Ethyl \(N\)-butylcarbamate Propose a mechanism for this reaction.

Complete the following transesterification reaction (the stoichiometry is given in the equation).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free