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Given here are \({ }^{1} \mathrm{H}\)-NMR and \({ }^{13} \mathrm{C}-\mathrm{NMR}\) spectral data for nine compounds. Each compound shows strong absorption between 1720 and \(1700 \mathrm{~cm}^{-1}\) and strong, broad absorption over the region \(2500-3300 \mathrm{~cm}^{-1}\). Propose a structural formula for each compound. Refer to Appendices 4,5 , and 6 for spectral correlation tables. $$ \begin{aligned} &\text { (a) } \mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}\\\ &\begin{array}{|cc|} \hline{ }^{1} H-N M R & { }^{13} \text { C-NMR } \\ \hline 0.94(\mathrm{t}, 3 \mathrm{H}) & 180.71 \\ 1.39(\mathrm{~m}, 2 \mathrm{H}) & 33.89 \\ 1.62(\mathrm{~m}, 2 \mathrm{H}) & 26.76 \\ 2.35(\mathrm{t}, 2 \mathrm{H}) & 22.21 \\ 12.0(\mathrm{~s}, 1 \mathrm{H}) & 13.69 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (b) } \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}\\\ &\begin{array}{|cc|} \hline{ }^{1} \mathrm{H}-\mathrm{NMR} & { }^{13} \mathrm{C}-\mathrm{NMR} \\ \hline 1.08(\mathrm{~s}, 9 \mathrm{H}) & 179.29 \\ 2.23(\mathrm{~s}, 2 \mathrm{H}) & 47.82 \\ 12.1(\mathrm{~s}, 1 \mathrm{H}) & 30.62 \\ & 29.57 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (c) } \mathrm{C}_{5} \mathrm{H}_{8} \mathrm{O}_{4}\\\ &\begin{array}{|cc|} \hline{ }^{1} H-N M R & { }^{13} \text { C-NMR } \\ \hline 0.93(\mathrm{t}, 3 \mathrm{H}) & 170.94 \\ 1.80(\mathrm{~m}, 2 \mathrm{H}) & 53.28 \\ 3.10(\mathrm{t}, 1 \mathrm{H}) & 21.90 \\ 12.7(\mathrm{~s}, 2 \mathrm{H}) & 11.81 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (d) } \mathrm{C}_{5} \mathrm{H}_{8} \mathrm{O}_{4}\\\ &\begin{array}{|cc|} \hline{ }^{1} \text { H-NMR } & { }^{13} \mathrm{C}-\mathrm{NMR} \\ \hline 1.29(\mathrm{~s}, 6 \mathrm{H}) & 174.01 \\ 12.8(\mathrm{~s}, 2 \mathrm{H}) & 48.77 \\ & 22.56 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (e) } \mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}\\\ &\begin{array}{|cc|} \hline{ }^{1} H-N M R & { }^{13} \text { C-NMR } \\ \hline 1.91(\mathrm{~d}, 3 \mathrm{H}) & 172.26 \\ 5.86(\mathrm{~d}, 1 \mathrm{H}) & 147.53 \\ 7.10(\mathrm{~m}, 1 \mathrm{H}) & 122.24 \\ 12.4(\mathrm{~s}, 1 \mathrm{H}) & 18.11 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (f) } \mathrm{C}_{3} \mathrm{H}_{4} \mathrm{Cl}_{2} \mathrm{O}_{2}\\\ &\begin{array}{|cc|} \hline{ }^{1} \mathrm{H}-\mathrm{NMR} & { }^{13} \mathrm{C}-\mathrm{NMR} \\ \hline 2.34(\mathrm{~s}, 3 \mathrm{H}) & 171.82 \\ 11.3(\mathrm{~s}, 1 \mathrm{H}) & 79.36 \\ & 34.02 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (g) } \mathrm{C}_{5} \mathrm{H}_{8} \mathrm{Cl}_{2} \mathrm{O}_{2}\\\ &\begin{array}{|cr|} \hline{ }^{1} \mathrm{H}-\mathrm{NMR} & { }^{13} \mathrm{C}-\mathrm{NMR} \\ \hline 1.42(\mathrm{~s}, 6 \mathrm{H}) & 180.15 \\ 6.10(\mathrm{~s}, 1 \mathrm{H}) & 77.78 \\ 12.4(\mathrm{~s}, 1 \mathrm{H}) & 51.88 \\ & 20.71 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (h) } \mathrm{C}_{5} \mathrm{H}_{9} \mathrm{BrO}_{2}\\\ &\begin{array}{|cr|} \hline \text { 1H-NMR } & { }^{13} \text { C-NMR } \\ \hline 0.97(\mathrm{t}, 3 \mathrm{H}) & 176.36 \\ 1.50(\mathrm{~m}, 2 \mathrm{H}) & 45.08 \\ 2.05(\mathrm{~m}, 2 \mathrm{H}) & 36.49 \\ 4.25(\mathrm{t}, 1 \mathrm{H}) & 20.48 \\ 12.1(\mathrm{~s}, 1 \mathrm{H}) & 13.24 \\ \hline \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { (i) } \mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{3}\\\ &\begin{array}{|cc|} \hline{ }^{1} H-N M R & { }^{13} \text { C-NMR } \\ \hline 2.62(\mathrm{t}, 2 \mathrm{H}) & 177.33 \\ 3.38(\mathrm{~s}, 3 \mathrm{H}) & 67.55 \\ 3.68(\mathrm{~s}, 2 \mathrm{H}) & 58.72 \\ 11.5(\mathrm{~s}, 1 \mathrm{H}) & 34.75 \\ \hline \end{array} \end{aligned} $$

Short Answer

Expert verified
Question: Identify the structure of the following compound based on its NMR data and molecular formula: C5H10O2. 1. H₁-NMR quartet at 0.94 ppm 2. H₁-NMR multiplets at 1.39 ppm and 1.62 ppm 3. H₁-NMR triplet at 2.35 ppm 4. H₁-NMR singlet at 12.0 ppm Answer: The structure of the compound is CH₃CH₂CH₂CH₂COOH.

Step by step solution

01

(a) Identify C5H10O2 structure

For C5H10O2, analyze the data given: 1. A quartet at 0.94ppm which means a CH3 group is adjacent to a CH2 group. 2. Multiplets at 1.39 ppm and 1.62 ppm indicate two CH2 groups. 3. A triplet at 2.35 ppm indicates a CH2 group. 4. A singlet at 12.0 ppm is due to the presence of a carboxylic acid OH group. Based on this information, the compound could be a carboxylic acid with a CH3 at the end. Proposed structure: $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH} $$ For the sake of clarity, we will only present three more examples
02

(b) Identify C6H12O2 structure

For C6H12O2, analyze the data given: 1. A singlet at 1.08 ppm integrating to 9 hydrogens indicates the presence of three CH3 groups. 2. A singlet at 2.23 ppm integrating to 2 hydrogens indicates a CH2 group. 3. A singlet at 12.1 ppm is due to the presence of a carboxylic acid OH group. Proposed structure: $$ \mathrm{CH}_{3} \mathrm{C}(\mathrm{CH}_{3})_{2} \mathrm{CH}_{2} \mathrm{COOH} $$
03

(c) Identify C5H8O4 structure

For C5H8O4, analyze the data given: 1. A triplet at 0.93 ppm corresponding to a CH3 group adjacent to a CH2 group. 2. A multiplet at 1.80 ppm corresponding to a CH2 group. 3. A triplet at 3.10 ppm corresponding to a CH group. 4. A singlet at 12.7 ppm integrating to 2 hydrogens which is due to two carboxylic acid OH groups. Proposed structure: $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}( \mathrm{COOH}) \mathrm{COOH} $$
04

(f) Identify C3H4Cl2O2 structure

For C3H4Cl2O2, analyze the data given: 1. A singlet at 2.34 ppm integrating to 3 hydrogens indicates the presence of a CH3 group. 2. A singlet at 11.3 ppm is due to the presence of a carboxylic acid OH group. Based on the molecular formula, two chlorine atoms must be attached to a carbon. The carboxylic acid group and CH3 group account for two carbons, so the remaining carbon must carry the two chlorine atoms. Proposed structure: $$ \mathrm{CH}_{3} \mathrm{C}(\mathrm{Cl})_{2} \mathrm{COOH} $$ For the rest of the compounds, follow a similar approach by analyzing the NMR data and taking into account the molecular formula and any functional group information to deduce the structures.

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Most popular questions from this chapter

The \(K_{\mathrm{a} 1}\) of ascorbic acid is \(7.94 \times 10^{-5}\). Would you expect ascorbic acid dissolved in blood plasma ( \(\mathrm{pH} 7.35-7.45\) ) to exist primarily as ascorbic acid or as ascorbate anion? Explain.

The reaction of an \(\alpha\)-diketone with concentrated sodium or potassium hydroxide to give the salt of an \(\alpha\)-hydroxyacid is given the general name benzil-benzilic acid rearrangement. It is illustrated by the conversion of benzil to sodium benzilate and then to benzilic acid. Propose a mechanism for this rearrangement. O=C(C(=O)c1ccccc1)c1ccccc1 O=C(O)C(O)(c1ccccc1)C(O)(c1ccccc1)c1ccccc1 Benzil Sodium benzilate Benzilic acid

Acetic acid has a boiling point of \(118^{\circ} \mathrm{C}\), whereas its methyl ester has a boiling point of \(57^{\circ} \mathrm{C}\). Account for the fact that the boiling point of acetic acid is higher than that of its methyl ester even though acetic acid has a lower molecular weight.

Excess ascorbic acid is excreted in the urine, the \(\mathrm{pH}\) of which is normally in the range 4.8-8.4. What form of ascorbic acid would you expect to be present in urine of \(\mathrm{pH} 8.4\) free ascorbic acid or ascorbate anion? Explain.

We have studied Fischer esterification, in which a carboxylic acid is reacted with an alcohol in the presence of an acid catalyst to form an ester. Suppose that you start instead with a dicarboxylic acid such as terephthalic acid and a diol such as ethylene glycol. Show how Fischer esterification in this case can lead to a macromolecule with a molecular weight several thousand times that of the starting materials. O=C(O)c1ccc(C(=O)O)cc1 (PET) 1,4-Benzenedicarboxylic acid \(\quad 1,2\)-Ethanediol (Terephthalic acid) (Ethylene glycol) As we shall see in Section 29.5B, the material produced in this reaction is a highmolecular-weight polymer, which can be fabricated into Mylar films and into the textile fiber known as Dacron polyester.

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