Question

CCC (d) O=CO (c… # UseVSEPR to predict bond angles about each highlighted atom. (a) CCCO (b) C=CBr (c) C#CCC (d) O=CO (c) \(\mathrm{H}-\mathrm{O}_{*}^{*}-\mathrm{N}=\ddot{\mathrm{O}}_{*}\) (f) CN

Short answer

Answer: The ideal bond angle is 120°. 2. What is the electron pair geometry and molecular geometry of the molecule C=CBr around the highlighted carbon atom? Answer: The electron pair geometry and molecular geometry is trigonal planar. 3. What are the ideal bond angles in a tetrahedral molecule? Answer: The ideal bond angles in a tetrahedral molecule are 109.5°.

Step-by-step solution

(a) CCCO

Identify the electron pair geometry and molecular geometry around the highlighted atom in CCCO. The carbon atom has three sigma bonds and no lone pairs. Hence, the electron pair geometry is trigonal planar, and the molecular geometry is also trigonal planar. The ideal bond angles in a trigonal planar molecule are 120°.

(b) C=CBr

Identify the electron pair geometry and molecular geometry around the highlighted atom in C=CBr. The carbon atom has two sigma bonds, one pi bond, and no lone pairs. Hence, the electron pair geometry is trigonal planar, and the molecular geometry is also trigonal planar. The ideal bond angles in a trigonal planar molecule are 120°.

(c) C#CCC

Identify the electron pair geometry and molecular geometry around the highlighted atom in C#CCC. The carbon atom has two sigma bonds (one single bond and one triple bond) and no lone pairs. Hence, the electron pair geometry is linear, and the molecular geometry is also linear. The ideal bond angles in a linear molecule are 180°.

(d) O=CO

Identify the electron pair geometry and molecular geometry around the highlighted atom in O=CO. The oxygen atom has two sigma bonds and two lone pairs. Hence, the electron pair geometry is tetrahedral, and the molecular geometry is bent. The ideal bond angle for a bent molecule with a tetrahedral electron pair geometry is approximately 104.5°.

(e) H-O-N=O

Identify the electron pair geometry and molecular geometry around the highlighted oxygen atom in \(\mathrm{H}-\mathrm{O}_{*}^{*}-\mathrm{N}=\ddot{\mathrm{O}}_{*}\). The oxygen atom has two sigma bonds and two lone pairs. Hence, the electron pair geometry is tetrahedral, and the molecular geometry is bent. The ideal bond angle for a bent molecule with a tetrahedral electron pair geometry is approximately 104.5°.

(f) CN

Identify the electron pair geometry and molecular geometry around the highlighted atom in CN. The carbon atom has four sigma bonds and no lone pairs. Hence, the electron pair geometry is tetrahedral, and the molecular geometry is also tetrahedral. The ideal bond angles in a tetrahedral molecule are 109.5°.