Chapter 1: Problem 34
Why does fluorine, the element in the upper right corner of the Periodic Table, have the largest electronegativity of any element?
Chapter 1: Problem 34
Why does fluorine, the element in the upper right corner of the Periodic Table, have the largest electronegativity of any element?
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Get started for freeDraw structural formulas for (a) The eight alcohols with the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\). (b) The eight aldehydes with the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}\). (c) The six ketones with the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}\). (d) The eight carboxylic acids with the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}\). (e) The nine carboxylic esters with the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}\).
Draw a three-dimensional representation for each molecule. Indicate which ones have a dipole moment and in what direction it is pointing. (a) \(\mathrm{CH}_{3} \mathrm{~F}\) (b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) (c) \(\mathrm{CH}_{2} \mathrm{ClBr}\) (d) \(\mathrm{CFCl}_{3}\) (e) \(\mathrm{CCl}_{4}\) (f) \(\mathrm{CH}_{2}=\mathrm{CCl}_{2}\) (g) \(\mathrm{CH}_{2}=\mathrm{CHCl}\) (h) \(\mathrm{HC} \equiv \mathrm{C}-\mathrm{C} \equiv \mathrm{CH}\) (i) \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{N}\) (j) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}\) (k) \(\mathrm{BrCH}=\mathrm{CHBr}\) (two answers)
Using the symbols \(\delta-\) and \(\delta+\), indicate the direction of polarity in each polar covalent bond. (a) \(\mathrm{C}-\mathrm{N}\) (b) \(\mathrm{N}-\mathrm{O}\) (c) \(\mathrm{C}-\mathrm{Cl}\)
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(d)
Which statements are true about electronegativity? (a) Electronegativity increases from left to right in a period of the Periodic Table. (b) Electronegativity increases from top to bottom in a column of the Periodic Table. (c) Hydrogen, the element with the lowest atomic number, has the smallest electronegativity. (d) The higher the atomic number of an element, the greater its electronegativity.
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