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Define valence shell and valence electron.

Short Answer

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Question: Define valence shell and valence electron, and provide the valence shell and number of valence electrons for sodium and oxygen. Answer: The valence shell is the outermost shell of an atom that contains electrons, and these electrons are responsible for chemical bonding. A valence electron is an electron present in the valence shell that determines the atom's chemical behavior. For sodium (Na), the valence shell is the third shell (3s¹), with one valence electron. For oxygen (O), the valence shell is the second shell (2s² 2p⁴), with six valence electrons.

Step by step solution

01

Definition of Valence Shell

The valence shell is the outermost shell (energy level) of an atom that contains electrons. These electrons are involved in chemical bonding, which leads to the formation of molecules and compounds. The valence shell is important because it determines an atom's reactivity and how it will interact with other atoms.
02

Definition of Valence Electron

A valence electron is an electron present in the valence shell of an atom. These electrons are responsible for an atom's chemical behavior, as they are used to form bonds with other atoms. The number of valence electrons affects the reactivity and stability of an element, as atoms typically strive to have a full valence shell (usually eight electrons, following the octet rule).
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Example: Sodium

In the case of sodium (Na), it has an atomic number of 11. Its electron configuration is 1s² 2s² 2p⁶ 3s¹. The valence shell would be the third shell, as it is the outermost shell occupied by electrons (3s¹). The valence electron is the single electron in this third shell (3s¹).
04

Example: Oxygen

For oxygen (O), with an atomic number of 8, the electron configuration is 1s² 2s² 2p⁴. The valence shell is the second shell containing 2s² and 2p⁴ electrons. Oxygen has six valence electrons in the second shell, consisting of two 2s electrons and four 2p electrons.

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Most popular questions from this chapter

Judging from their relative positions in the Periodic Table, which atom in each set is more electronegative? (a) Carbon or nitrogen (b) Chlorine or bromine (c) Oxygen or sulfur

Each compound contains both ions and covalent bonds. Draw the Lewis structure for each compound. Show with dashes which are covalent bonds and show with charges which are ions. (a) Sodium methoxide, \(\mathrm{CH}_{3} \mathrm{ONa}\) (b) Ammonium chloride, \(\mathrm{NH}_{4} \mathrm{C}\) (c) Sodium bicarbonate, \(\mathrm{NaHCO}_{3}\) (d) Sodium borohydride, \(\mathrm{NaBH}_{4}\) (e) Lithium aluminum hydride, \(\mathrm{LiAlH}_{4}\)

In Chapter 6, we study a group of organic cations called carbocations. Following is the structure of one such carbocation, the tert-butyl cation. CC(C)=C(C(=O)O)c1ccccc1 (a) How many electrons are in the valence shell of the carbon bearing the positive charge? (b) UsingVSEPR, predict the bond angles about this carbon. (c) Given the bond angle you predicted in (b), what hybridization do you predict for this carbon?

Write Lewis structures for these compounds. Show all valence electrons. None of them contains a ring of atoms. (a) Hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\) (b) Hydrazine, \(\mathrm{N}_{2} \mathrm{H}_{4}\) (c) Methanol, \(\mathrm{CH}_{3} \mathrm{OH}\)

Draw a Lewis structure for methyl isocyanate, \(\mathrm{CH}_{3} \mathrm{NCO}\), showing all valence electrons. Predict all bond angles in this molecule and the hybridization of each \(\mathrm{C}, \mathrm{N}\), and \(\mathrm{O}\).

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