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Draw the transition state for each reaction.

a.

b.

Short Answer

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Answer

a. Transition state of a.

b.Transition state of b.

Step by step solution

01

Step-by-Step SolutionStep 1: Transition State

In a concerted reaction mechanism, the transition state is a particular configuration of the reactant that has the highest potential energy.

The Transition state is an intermediate structure in which the bond to be broken and the new bond to be formed are represented with dashed lines in the transition state of the compound.

The old dashed bonds mean that the old bonds are partially broken, and the new dashed bonds mean that the new bonds are partly formed.

02

Charge on the transition state

For a reactant that contains a negative or a positive charge, the transition state of this reactant would contain partial charges of either one.

03

Transition State of the given compounds

a. As the O-H bond partially breaks, the hydrogen forms a new bond partially with NH2-. This gives the transition state of the reaction coordinates. In this structure, the O-H-N bonds are shown with dashed lines, and all these three atoms share a partial negative charge δ-density.

Transition state of a.

b. A C-H bond is breaking off from tertiary carbocation, and a new O-H bond is forming inH2O. Hence, the transition state consists of a molecule in which both the reactants are attached with dashed (partial) bonds.

Transition state of b.

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Most popular questions from this chapter

Draw the products of homolysis or heterolysis of each indicated bond. Use electronegativity differences to decide on the location of charges in the heterolysis reaction. Classify each carbon reactive intermediate as a radical, carbocation, or carbanion.

a.

b.

The equilibrium constant for the conversion of the axial to the equatorial conformation of methoxycyclohexane is 2.7.


  1. Given these data, which conformation is present in the larger amount at equilibrium?
  2. Is ΔG° for this process positive or negative?
  3. From the values in Table 6.3, approximate the size of ΔG°.

For a reaction with Keq=0.8and Ea=80kJ/mol, decide which of the following statements is (are) true. Correct any false statement to make it true. Ignore entropy considerations. (a) The reaction is faster than a reaction with Keq=8and Ea=80kJ/mol. (b) The reaction is faster than a reaction with Keq=0.8and Ea=40kJ/mol. (c) G° for the reaction is a positive value. (d) The starting materials are lower in energy than the products of the reaction. (e) The reaction is exothermic.

Draw an energy diagram for each reaction. Label the axes, the starting material, product, transition state, ΔH°, and Ea.

a.a concertedwith ΔH°=-80kJ/moland Ea=16kJ/mol.

b. a two-step reaction, ABC, in which the relative energy of the compounds is A<C<B, and the step ABis rate-determining.

Label each statement as true or false. Correct any false statement to make it true.

a. Increasing temperature increases reaction rate.

b. If a reaction is fast, it has a large rate constant.

c. A fast reaction has a large negative G°value.

d. When Eais large, the rate constant k is also large.

e. Fast reactions have equilibrium constants > 1.

f. Increasing the concentration of a reactant always increases the rate of a reaction.

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