Question

Question: Convert each condensed formula to a Lewis structure

$$\begin{gathered} \mathbf{a}\mathbf{.}\mathbf{}{\mathbf{CH}}_{\mathbf{3}}{\left({\mathrm{CH}}_2\right)}_{\mathbf{4}}\mathbf{CH}{\left({\mathrm{CH}}_3\right)}_{\mathbf{2}} \\ \mathbf{b}\mathbf{.}\mathbf{}{\left({\mathrm{CH}}_3\right)}_{\mathbf{3}}\mathbf{CCH}\left(\mathrm{OH}\right){\mathbf{CH}}_{\mathbf{2}}{\mathbf{CH}}_{\mathbf{3}} \\ \mathbf{c}\mathbf{.}\mathbf{}{\left({\mathrm{CH}}_3\right)}_{\mathbf{2}}\mathbf{CHCHO} \\ \mathbf{d}\mathbf{.}\mathbf{}{\left({\mathrm{OHCH}}_2\right)}_{\mathbf{2}}\mathbf{CH}{\left({\mathrm{CH}}_2\right)}_{\mathbf{3}}\mathbf{C}{\left({\mathrm{CH}}_3\right)}_{\mathbf{2}}{\mathbf{CH}}_{\mathbf{2}}{\mathbf{CH}}_{\mathbf{3}} \end{gathered}$$

Short answer

Answer

a.

b.

c.

d.

Step-by-step solution

Step-by-Step Solution Step 1: Lewis structure

The Lewis structure of a compound can be represented by showing the valence electrons of each atom.

Construction of Lewis structure

a. Here, each carbon atom has valency four and each hydrogen atom with valency one.

Lewis structure of a

b. The alcohol group is the functional group here, and the oxygen atom contains 2 lone pairs.

Lewis structure of b

c. Carbonyl group is the functional group here, and the oxygen atoms contain two lone pairs.

Lewis structure of c

d. There are two hydroxyl groups present in it, and each oxygen atom contains two lone pairs.

Lewis structure of d