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Chapter 1: Q13. (page 22)

Question: Use curved arrow notation to show how the first resonance structure can be converted to the second.
a.
b.

Short Answer

Expert verified

Answer

a.

b.

Step by step solution

01

Step-by-Step Solution Step 1: Curved arrow mechanism

The curved arrows portray the electrons’ movement, and the bond breaking and forming processare explained. The tail part of the arrow displays the origination of the electron.

02

Representation of curved arrow mechanism

a. For the formation of the second resonance structure, the electrons in the double bond get shifted to the carbon-carbon bond. A double bond formation happens, and the positive charge on carbon gets shifted.

The curved arrow mechanism of the first structure

b. The negative charge on oxygen shifts to the carbon-oxygen bond, which tends to move the electrons in the double bond. Hence, a double bond is formed first, followed by a single bond.

The curved arrow mechanism of the second structure

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Most popular questions from this chapter

Question: Draw all reasonable resonance structures for each species.

$a . {O_{3}}^{-} b . {NO}_{3}^{-} (a central N atom) c . {N_{3}}^{-}$

d.

e.

Question: Follow the curved arrows to draw a second resonance structure for each species.

a.

b.

Question: Draw Lewis structures for the nine isomers having a molecular formula $C_{3} H_{6} O$ , with all atoms having a zero formal charge.

Question: The principles of this chapter can be applied to organic molecules of any size. Answer the following questions about amoxicillin, an antibiotic from the penicillin family:

a. Predict the hybridization and geometry around each highlighted atom.

b. Label five polar bonds using the symbols $δ^{+} and δ^{-}$ .

c. How many π bonds does amoxicillin have? Label them.

d. Find a C- H bond containing a carbon atom having a hybrid orbital with 33% s character.

Question: Draw a second resonance structure for each species in parts (a) and (b). Draw two additional resonance structures for the ion in part (c).

a.

b.

c.

See all solutions

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