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Rank the following groups in order of decreasing priority.

  1. -F,-NH2,-CH3,-OH
  2. -CH3,-CH2CH3,-CH2CH2CH3,-(CH2)3CH3
  3. -NH2,-CH2NH2,-CH3,-CH2NHCH3
  4. -COOH,-CH2OH,-H,-CHO
  5. -Cl,-CH3,-SH,-OH
  6. -C≡CH,-CH(CH3)2,-CH2CH3,-CH=CH2

Short Answer

Expert verified
  1. -F>-OH>-NH2>-CH3
  2. -(CH2)3CH3>-CH2CH2CH3>-CH2CH3>-CH3
  3. -NH2>-CH2NHCH3>-CH2NH2>-CH3
  4. -COOH>-CHO>-CH2OH>-H
  5. -Cl>-SH>-OH>-CH3
  6. -C≡CH>-CH=CH2>-CH(CH3)2>-CH2CH3

Step by step solution

01

Assigning the R and S nomenclature

The R and S nomenclature is used to name the enantiomers. The enantiomers of a compound are considered separate compounds. Each group that is directly bonded to the stereocenter is assigned a priority.

Based on this priority, the enantiomers are named R and S along with their IUPAC names.

02

Rules to assign priority

There are rules used to assign priority to each group connected to the stereogenic center. By using this, the enantiomers are labeled as R or S.

Following are the rules to assign the priorities to various groups:

  • The atom with the highest atomic number, directly bonded to the stereogenic center, gets the highest priority.
  • For isotopes, the isotope with the highest mass number gets priority over the other isotopes.
  • In the case of the multiple bonds, they are counted as the equal number of singly bonded atoms.
  • In the case of the same atoms bonded to the stereocenter, the atom bonded next is considered for assigning priority.
03

Ranking of the groups in orders of the decreasing priority

a.-F,-NH2,-CH3,-OH

The order of decreasing priority for the above groups is as follows:

-F>-OH>-NH2>-CH3

The fluorine atom has the highest atomic number. Hence, it gets the first priority. The atomic number of the carbon atom is the lowest among the group. It gets the least priority.

b.-CH3,-CH2CH3,-CH2CH2CH3,-(CH2)3CH3

The order of decreasing priority for the above groups is as follows:

-(CH2)3CH3>-CH2CH2CH3>-CH2CH3>-CH3

The group which has more carbon atoms gets the highest priority as compared to the other groups.

c.-NH2,-CH2NH2,-CH3,-CH2NHCH3

The order of decreasing priority for the above groups is as follows:

-NH2>-CH2NHCH3>-CH2NH2>-CH3

The nitrogen atom has the highest atomic number and gets the highest priority. In the second group, the secondary amine gets the second priority, followed by the primary amine.

In the case of secondary amine, the nitrogen atom is bonded to the carbon atom and gets priority over the primary amine.

d.-COOH,-CH2OH,-H,-CHO

The order of decreasing priority for the above groups is as follows:

-COOH>-CHO>-CH2OH>-H

The carboxylic acid gets the highest priority because the carbon atom is bonded to two other oxygen atoms.

The aldehyde group gets priority over the alcohol because, in aldehyde, the carbon atom forms a double bond with an oxygen atom.

e.localid="1648450198972" -Cl,-CH3,-SH,-OH

The order of decreasing priority for the above groups is as follows:

localid="1648450206131" -Cl>-SH>-OH>-CH3

The chlorine atom has the highest atomic number, followed by sulfur, oxygen, and a carbon atom.

f.localid="1648450216329" -C≡CH,-CH(CH3)2,-CH2CH3,-CH=CH2

The order of decreasing priority for the above groups is as follows:

localid="1648450223735" -C≡CH>-CH=CH2>-CH(CH3)2>-CH2CH3

The group in which the carbon atom is forming a triple bond gets the highest priority, followed by the group with a carbon-carbon double bond.

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Most popular questions from this chapter

A sulfonium ion (R3S+) is a stereogenic center if three different alkyl groups are bonded to sulfur because sulfur is surrounded by four different groups, including its lone pair. In assigning an R or S designation to sulfur, the lone pair is always assigned the lowest priority (4). SAM, S-adenosylmethionine, is a biologically active sulfonium ion that we will learn about in Section 7.16. Locate all the stereogenic centers in SAM, and assign an R,S designation to each center.

Which of the following cyclic molecules are meso compounds?

a.

b.

c.

a. Locate all the tetrahedral stereogenic centers in discodermolide, a tumor inhibitor isolated from the Caribbean marine sponge Discodermiadissoluta.

b. Certain carbon–carbon double bonds can also be stereogenic centers. With reference to the definition in Section 5.3, explain how this can occur, and then locate the three additional stereogenic centers in discodermolide.

c. Considering all stereogenic centers, what is the maximum number of stereoisomers possible for discodermolide?

The [α] of pure quinine, an antimalarial drug, is –165.

a. Calculate the ee of a solution with the following [α] values: –50, –83, and –120.

b. For each ee, calculate the percent of each enantiomer present.

c. What is [α] for the enantiomer of quinine?

d. If a solution contains 80% quinine and 20% of its enantiomer, what is the ee of the solution?

e. What is [α] for the solution described in part (d)?

Drawn are four isomeric dimethylcyclopropanes.

a. How are the compounds in each pair related (enantiomers, diastereomers, constitutional isomers): A and B; A and C; B and C; C and D?

b. Label each compound as chiral or achiral.

c. Which compounds, alone, would be optically active?

d. Which compounds have a plane of symmetry?

e. How do the boiling points of the compounds in each pair compare: A and B; B and C; C and D?

f. Which of the compounds are meso compounds?

g. Would an equal mixture of compounds C and D be optically active? What about an equal mixture of B and C?

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