Chapter 15: Q35. (page 570)
Question: What is the major monobromination product formed by heating each alkane with Br2 ?
Short Answer
Answer
Chapter 15: Q35. (page 570)
Question: What is the major monobromination product formed by heating each alkane with Br2 ?
Answer
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Get started for freeQuestion: The triphenylmethyl radical is an unusual persistent radical present in solution in equilibrium with its dimer. For 70 years the dimer was thought to be hexaphenylethane, but in 1970, NMR data showed it to be A.
a. Why is the triphenylmethyl radical more stable than most other radicals?
b. Use curved arrow notation to show how two triphenylmethyl radicals dimerize to form A.
c. Propose a reason for the formation of A rather than hexaphenylethane.d. How could 1 H and 13C NMR spectroscopy be used to distinguish between hexaphenylethane and A?
Question: a) Draw all constitutional isomers formed by monochlorination of each alkane with Cl2and hฮฝ. (b) Draw the major monobromination product formed by heating each alkane with Br2.
Question: What monomer is needed to form each polymer?
a.
b.
Question: Draw a stepwise mechanism for the following addition reaction to an alkene.
Questions: Draw all constitutional isomers formed by monochlorination of each alkane.
a.
b.
c.
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